I am not 100% sure on this, so others can correct me if I'm wrong (because I'm doing Spesh 3/4 next year).
It would be much easier to understand if you simply drew a diagram. However, I will try my best:
Pretty much when you are completing a resolute, you are finding the projection of two different vectors in the direction of one of them.
Let there be two vectors 'a' and 'b'. Throughout these explanations, we will be carrying out a resolute of 'a' and 'b' in the direction of 'b'.
So, the scalar resolute of a and b is defined as the projection of vector 'a' times the projection of 'b'. In order to find the scalar resolute, we use the dot product. In this case, it would be a.b. I'm assuming you know how to carry out a dot product - its pretty simple anyway.
Now, when you find the dot product, you realise that its a scalar quantity (i.e. a magnitude with no direction), whereas vectors have a direction as well. Therefore, when you actually want to find the vector itself, you must find the magnitude, which is the scalar resolute and multiply it by the unit vector.
i.e. The vector resolute of 'a' and 'b' in the direction of 'b' is found by the scalar resolute multiplied by the unit vector of 'b'. Therefore, it is (a.b) x b(hat).
Notes:
- The scalar resolute is in fact, the "magnitude" of the vector resolute.
- Often, they will ask you to find the vector resolute of 'a' and 'b' parallel to the direction of 'b'. If you draw a right-angled triangle, you will quickly see, it is simple the vector 'a' subtracted by the vector resolute (a.b) x b(hat)
Yeah, I dont think I explained it well enough - tell me if I didn't. Nonetheless, a simple diagram will make it much more easier to understand.