suggested exam solutions

[Mao]

Is there anywhere we can get a copy of the exam online? Or is anyone who has it able to put it up?

we would, except neither of us have a scanner...

if you'd like a particular question to be posted up, say so and I'll try my best to replicate [but no guarantees on the diagrams ]

[chid]

Yeah, both 'bridge' questions if you can.

That would be great.

[Mao]

its up on the first post.

[anonymous12]

For question 17 can you do.

This is a pre-transposed equation for T that I found.
T= ((4*pi^2*R^3)/g)^(1/2)

Use R as 3.83*10^6
      g=2.91

then I got T=2.7*10^10

am I wrong?

that is wrong.

your formula is suggesting that:

, where

that'll create , which is really a bad transposing from keplar's law.


what your formula should have read is

[ps btw 2000 posts, woot, lol]

Do I get zero marks due to the incorrect formula I used? Please say no.
I've stated the correct R value, g value and G value.

[zzdfa]

Captain, (or anyone else who has the exam paper), Q12 Further electronics, was it asking for power dissapation over the 10kO resistor or the 10O resistor? Was there even a 10kO resistor in the circuit?

it was the 10 ohms resistor

Argh. That's 4 marks I've lost from misreading a question. damn multiple choice.

[Skullmaster4]

Sweet,

My answers where actually rather like Mao's

I'm starting to see hope now!!

P.s   I'm in the same specialist maths class as Mao..

He kills me

(This is David btw Mao )

[dcc]

Sweet,

My answers where actually rather like Mao's

I'm starting to see hope now!!

P.s   I'm in the same specialist maths class as Mao..

He kills me

(This is David btw Mao )

lol Mao's spec class only has 2 people, from what I hear

[bigtick]

i'm in the same class

[Fidgey]

can someone put up the last relativity question....

[anonymous12]

Can someone plz answer my question?

[Mao]

Can someone plz answer my question?

mmm, I cant guarantee sorry

and hi David


btw bigtick are you in Narre south or lyndhurst? I think i might have an idea who you might be

[chid]

Can someone plz answer my question?

I remember reading somewhere (might have been an assessment report and I think coblin mentioned it one time) that using the derived projectile motion formulas was 'all or nothing.' If you got the answer wrong it was zero but if you got the answer right then you got full marks. I think that applies here as well. I hope for your sake that you get a mark for your working though. (I cant stand losing marks when you don't deserve to lose them)

[Skullmaster4]

I'm the second person,

Atleast I'm guaranteed second place

On a further note he is also in my physics and Chem classes..

I can't escape him

[bigtick]

well i have a query..

"Question 8
XY is under obvious tension, A

Question 9
the stress experienced by YZ is:

B, compression
this one took a while
both ZX and XY are under tension. at Z, a force is pulling it towards X, and Y, a force is pulling it towards X also. the horizontal components of these two forces can be resolved and shown that they pull towards the same centre of YZ, hence it is under compression.
it makes sense to think this way, as concrete is weak under tension, and structures have been designed to make the beam under compression to increase its lifetime and safety."


ALot of people reckon it was tension for both...and itute seems to agree with them...

http://itute.com/board/viewtopic.php?p=695#695