onur369's Methods Question Thread :)

[Halil]

Sub the value of -3 into it, make it equal to 144. and also sub in 2 and make it equal to -1. So you have two separate equations in the end. Then, you apply the simultaneous rule and solve for a and b.
 

[onur369]

Substitute 2 into x and make it equal to -1, than solve for a.
Than substitue -3 into x into the intial equation and make it equal to 144, solve it for b.
Once you solve it for B, add in the a value you found from the first process and substitue it into the second one to find b.
After finding b you can just sub it into the equation of a= .....

Then you will find a,b
a=2 b=-5

[Pandabear]

thanks..

[Abdulhai]

ONAAAAAAAAAAAAA

[onur369]

Ohhh the black snake

[Pandabear]

if (x-2) and (x+5) are factors of x^4+ax^3-11x^2-3x+b a and b are ??

[pi]

I would sub x=2 and x=-5 into the equation (separately) and simultaneously solve them for a and b.

[luken93]

Let

We know that












Sub a=3 into (1):




Sub a=3 and b=10 into 2 to check:

[onur369]

Got caught up with a stupid question, probably my most weakest area.

The equation of the image of y=x^2 under a shift to the left of 4 units, a dilation of by a factor of 2 in the y-direction and a shift downwards of 3 units is:
2y=(x+4)^2 -3
       or
y=2(x+4)^2 -3

[luken93]

Do you mean a dilation on the y-axis or?

[onur369]

the question says: a dilation of by a factor of 2 in the y-direction

[Pandabear]

Let

We know that












Sub a=3 into (1):




Sub a=3 and b=10 into 2 to check:

That was an awesome response thanks.

[Pandabear]

Got caught up with a stupid question, probably my most weakest area.

The equation of the image of y=x^2 under a shift to the left of 4 units, a dilation of by a factor of 2 in the y-direction and a shift downwards of 3 units is:
2y=(x+4)^2 -3
       or
y=2(x+4)^2 -3

answer should be 2y=(x+4)^2 -3

[onur369]

That's exactly what I thought.

[onur369]

Got stuck in another question:

(log3(x))^2 -4log3(x) +3 =0