VCE Chemistry Unit 3 Exam
Multiple Choice QuestionsQuestion 1B, 14.58mL
Question 2A, 5.13E9 molecules
Question 3Xylose is a compound that has five carbon atoms in each molecule and contains 40% carbon by mass. What is the molar mass of xylose?
C, Mr=150
Question 4D, Phenolpthalein red to colourless [base to acid]
Question 5D, Mr(Glu) > Mr(Val), and NMR is different
though the environments of the Z in Val and Leu are the similar, it should be noted that at least the integration trace would be different.
Question 6Aspirin is a compound widely used as a painkiller and to relieve the symptoms of fever. It can be produced by means of a reaction in which salicylic acid is one of the reagents.
The structures of aspirin and salicylic acid are shown below.
which of the following statements about aspirin is not correct?
A. Aspirin may be prepared by reaction between salicylic acid and CH3OH
B. Aspirin contains both an ester and a carboxylic acid functional group
C. Aspirin can undergo an acid-base reaction with NaHCO3
D. Aspirin may be prepared by reaction between salicylic acid and CH3COOH
A, aspirin

SA + methanol
Question 7C, alkene and amide
Question 8A, DNA
Question 9D, 150 molecules of G
Question 10B:
piece 2 will be most easily separated [less GC pairs]
strand W will be heavier, as both G and A are pyrimidine [two rings]
Question 11Gel electrophoresis is a technique that can be used to separate DNA fragments in forensic chemistry. The gel resulting from such a separation experiment carried out at pH 7 is shown below
X Y
: | | |
: | | |
: | | |
Which of the following statements about the experiment is not correct?
A. Fragment X has a higher molecular mass than fragment Y
B. Fragment Y moves through the gel at a faster rate than fragment X
C. The negative terminal of the power supply is connected to the end A of the gel
D. Under the conditions of this experiment, the DNA grament are positivelyu charged
D. Gel electrophoresis does not have positively charged DNA fragments in pH 7
Question 12A, identity is determined by retention time
Question 13D, relative amount is determined by area under the peak
Question 14C, AAS would not provide information about a biomolecule
Question 15D, magnetic field -> nucleic energy
Question 16How many structural isomers, each containing a double bond, have the molecular formula C5H10?
C, 5 isomers:
c-c-c-c=c
c-c-c=c-c
c-c-c=c
|
c
c-c-c=c
|
c
c-c=c-c
|
c
Question 17B, it has alkene (react with Br
2) as well as COOH (react with sodium carbonate)
Question 18C, condensation of 2235. the fact that water is lost during polymerisation has to be factored in.
Question 19B, linoic. there are two alkene groups.
Question 20A, Y is more volatile than Z
B and C are both false, and D: "Z has stronger covalent bonds" is not necessarily true
Short Answer QuestionsQuestion 1The percentage purity of powdered, impure magnesium sulfate, MgSO4, can be determined by gravimetric analysis. Shown below is the method used in one such analysis.
Method:
32.50 g of the impure magnesium sulfate is dissolved in water and the solution is made up to 500.0 mL in a volumetric flask.
Different volumes of 0.100 M BaCl2(aq) are added to six separate 20.00 mL samples to this solution. This precipitates the sulfate ions as barium sulfate. (equation cbf'd)
The precipitate from each sample is filtered, rinsed with de-ionised water and then dried to constant mass.
ResultsMass of impure magnesium sulfate = 32.50 g
Volume of volumetric flast = 500.0 mL
Volume of magnesium sulfate solution in each sample = 20.00mL
| sample | 1 | 2 | 3 | 4 | 5 | 6 |
| Volume of BaCl2 (mL) | 30.0 | 60.0 | 90.0 | 120.0 | 150.0 | 180.0 |
| mass of BaSO4 (g) | 0.704 | 1.41 | 2.00 | 2.00 | 2.00 | 2.00 |
a. Why is it necessary to rinse the precipitate with deionised water before drying? (1 mark)
-> to ensure there are no other ions present in the filtrate
b. Explain why the amount of BaSO4(s) precipitated remains constant for the last 4 samples tested even though more BaCl2 was added (1 mark)
BaCl2 is in excess
c i. calculate the amount of SO42-(aq) in the 500mL volumetric flask (2 marks)
0.214 mol
ii. calculate the percentage by mass of magnesium sulfate in the powder (2 marks)
79.4%
Six further 20.00mL samples of the manesium sulfate solutions are analysed. However, the concentration of the barium chloride added to those six samples is 0.200M
d (2 marks)
the graph:
30mL = 1.408 g of sample
line at ~45mL = 2g
all dots afterwards are at 2.00g
Question 2One method of analusing the manganese content of steel is to dissolve the steel in nitric acid, producing a solution of manganese II ions
the Mn2+ ions are then treated with an excess of acidified solution of periodate ions, I)
4-. The products of this reaction are iodate ions, IO3-, and the deeply purple coloured permanganate ions, MnO4-
The concetration of MnO4- is then determined by UV vis.
a i Calculate the oxidation number of iodine in IO4- (1 mark)
+7
ii. Give a half equation for the conversion of IO4- to IO3- (1 mark)
iii. is the IO4- ion acting as oxidant or reductant? (1 mark)
oxidant, it gains electrons
An experiment was carried out to determine the percentage of manganese in a particular sample of steel by the above method.
A 13.936 g sample of steel was dissolved in acid and the manganese was converted to MnO4-
The solution containing the MnO4- ions was filtered and made up to a volume of 1.00L
25.00mL of this solution was then futher diluted to a 100.0 mL in a volumetric flask. the absorbance, at 525 nm, of this solution was 0.70
[and a graph of standards giving 35mg/L]
b i. /what is the concentration of MnO4- in the diluted 100mL (1 mark)
from graph, 0.70 => 35 mg/L
ii. Calculate the mass of manganese in the steel sample (2 marks)
64.6 mg
iii. Calculate the percentage by mass of manganese in the steel sample (1 mark)
0.464%
Question 3a. write the reagent (1 mark)
CH
3COOH (or draw the structural formula)
b i. draw the component with Rf=0.4 when solvent from =5 (1 mark)
line at 2
ii. 4 aminophenol adsorbs less strongly to the stationary phase (1 mark)
Rf would be greater because:
less adsorption onto stationary -> more time in mobile -> more movement -> higher displacement -> higher Rf
c (1 mark)
this question is a bit nasty:

there will be a bit of leeway on this as it is interpreting the number from the graph. if you've wrote 1.6 for absorbance of first, the answer 9.06
Question 4Compount X at 120C, 115kPa, 0.376g occupies 124mL
a. Calculate the molar mass of X (2 marks)
86.1 g/mol
Compound Y is C
4H
10O
b i. draw the structural formulas (4 marks)
(i cbf doing it all out, but here's the general structures)
C-C-C-C-O
O
|
C-C-C-C
C-C-C-O
|
C
O
|
C-C-C
|
C
Y has 3 lines in C NMR, and react with Cr
2O
7- ii (2 marks)
Evidence from NMR: 3 carbon environments
Evidence from second reaction: 1-hydroxy (-OH is at the end of the backbone)
iii (2 marks)
2-methylpropan-1-ol
Compound Z has the molecular formula C5H10O, and shows a strong band in the infrared spectrum at about 1700
c i. (2 marks)
IR -> C=O group
NMR -> 2 H enviroments. CH3-CH2-
ii (1 mark)
hydrogen are not drawn
O
||
c-c-c-c-c
bahh! and we thought ketone wasnt on the course
Question 5a i. Draw the structure of serine in pH 2 (1 mark)
cbf.. H
3N
+-...
ii. Name the functional group on the side chain (1 mark)
hydroxy/hydroxyl, NOT alcohol
b. write the molecular formula for phenyalanine (1 mark)
C9H11NO2
c i. draw the structure of dipeptide (1 mark)
bah-
NH})
-hab
ii circle the amide/peptide (1 mark)
see above
d. sketch covalent link of the interaction between cysteine (1 mark)
-S-S-
disulfide
Question 6a. Give a systematic name for each of the following compounds i (2 marks)
ethylamine
ii (2 marks)
Cl c
| |
c-c-c-c-c-c
|
c
5-chloro,2-methylheptane
C3H7Cl + X -> K, K + Cr2O7
2-, H+ -> C3H6O2
+ H2SO4 -> methyl propanoate
L
b i. draw methyl propanoate (1 mark)
bah~O-(O=C)~bah
ii. draw K and L (2 marks)
K is 1-propanol (c-c-c-o)
L is methanol (c-o)
iii. write reagent X (1 mark)
NaOH
Question 7a. Write a chemical equation for the combustion of ethnaol in excess oxygen (2 marks)
b. Give chemical reasons why ethanol can mix with both water and petrol (2 marks)
-> OH functional group => miscible in water
-> hydrocarbon body => miscible in petrol
c. i. Write a chemical equation for the fermentation of glucose to produce ethanol (1 mark)
ii. Explain why ethanol produced by fermentation is refferred to as a "biochemical fuel" (1 mark)
it is a biological process in yeast, i.e. conversion of glucose [biological] into ethanol [fuel]
d. What fragment would have been lost from the molecular ion to accound for m/z of 45? (1 mark)
H in OH
Question 80.415g of pure acid, H2X, is added to exactly 100mL of 0.105M NaOH
A reaction occurs (etc)
The NAOH is in excess. This excess NaOH requires 25.12 mL of 0.197M Hcl for neutralisation
i. calculate the amount in mol of NaOH added initially (1 mark)
0.0105 mol
ii. calculate the amount in mol of NaOH that reacts with the acid H2X (2 marks)
5.53E-3 mol
iii. calculate the molar mass of H2X (2 marks)
150 g/mol
(i lost one mark here

forgot that it was diprotic

)