the molecule is called 3-chloro,6-methylheptane!
i honestly dont think i dropped a mark!!
only coz i owned biol last year though
nooobs
No, its not!
You have to count from the end of the chain CLOSEST to the functional group!
The thing that overrides this is the presence of a double bond!!
edit*thankyou coblin!
(i lost one mark here Tongue forgot that it was diprotic
Uhm, with this question (question 8, short answer) I didn't include anything to do with the thing being diprotic in my calculations, and I ended up with the same answers that Mao posted. (I'm assuming he posted the corrected answer)
From what I remember, I did use mol ratios, but nothing to do with something being diprotic, just that 2 NaOHs would react with one of the acid, which was common sense >.<