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November 08, 2025, 07:49:58 am

Author Topic: Exam Suggested Solutions  (Read 82095 times)  Share 

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ganges

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Re: Exam Suggested Solutions
« Reply #120 on: June 12, 2008, 08:27:56 pm »
FCK!! the significant figurees were so annoying!!!

Its really hard to keep track of ur significant figures in the middle of your exam!!!!

Are the examiners strict about this?
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jay.

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Re: Exam Suggested Solutions
« Reply #121 on: June 12, 2008, 08:28:43 pm »
oh no i put 6-methyl, 3-chloroheptane is that wrong

Collin Li

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Re: Exam Suggested Solutions
« Reply #122 on: June 12, 2008, 08:29:49 pm »
the molecule is called 3-chloro,6-methylheptane!
i honestly dont think i dropped a mark!!
only coz i owned biol last year though
 nooobs

We've been through this already:

http://butane.chem.uiuc.edu/cyerkes/Chem104A_BFA05/Genchemref/nomenclature_rules.html

"The halogen is treated as a substituent on an alkane chain. The halo- substituent is considered of equal rank with an alkyl substituent in the numbering of the parent chain."

The answer is 5-chloro-2-methylheptane.

Also, your comma is incorrect, it should be a hyphen.

Mao

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Re: Exam Suggested Solutions
« Reply #123 on: June 12, 2008, 08:31:03 pm »
the molecule is called 3-chloro,6-methylheptane!
i honestly dont think i dropped a mark!!
only coz i owned biol last year though
 nooobs


that's wrong, "infraredismybitch"

it is 5-chloro-2-methylheptane

or the less correct version

2-methyl-5-chloroheptane

pwnt :P
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Aba

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Re: Exam Suggested Solutions
« Reply #124 on: June 12, 2008, 08:33:32 pm »
wasnt there a double dilution for the manganese question, meaning the percentage of manganese was around 18%?????? thats wat ma friends says, i think he was right, cause his teacher said the same i think!

bucket

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Re: Exam Suggested Solutions
« Reply #125 on: June 12, 2008, 08:34:00 pm »
the molecule is called 3-chloro,6-methylheptane!
i honestly dont think i dropped a mark!!
only coz i owned biol last year though
 nooobs

No, its not!
You have to count from the end of the chain CLOSEST to the functional group!
The thing that overrides this is the presence of a double bond!!

edit*
thankyou coblin!

Quote
(i lost one mark here Tongue forgot that it was diprotic

Uhm, with this question (question 8, short answer) I didn't include anything to do with the thing being diprotic in my calculations, and I ended up with the same answers that Mao posted. (I'm assuming he posted the corrected answer)
From what I remember, I did use mol ratios, but nothing to do with something being diprotic, just that 2 NaOHs would react with one of the acid, which was common sense >.<
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Mao

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Re: Exam Suggested Solutions
« Reply #126 on: June 12, 2008, 08:36:25 pm »
Quote
(i lost one mark here Tongue forgot that it was diprotic

Uhm, with this question (question 8, short answer) I didn't include anything to do with the thing being diprotic in my calculations, and I ended up with the same answers that Mao posted. (I'm assuming he posted the corrected answer)
From what I remember, I did use mol ratios, but nothing to do with something being diprotic, just that 2 NaOHs would react with one of the acid, which was common sense >.<

yeah, because the mole ratio is 1:2 makes it diprotic :P
and i totally forgot about that and just assumed 1:1 xD [lol i'm an idiot]
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Mao

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Re: Exam Suggested Solutions
« Reply #127 on: June 12, 2008, 08:38:41 pm »
wasnt there a double dilution for the manganese question, meaning the percentage of manganese was around 18%?????? thats wat ma friends says, i think he was right, cause his teacher said the same i think!

nope, just thoroughly checked mine.

it was actually dissolve -> take aliquot -> dilute -> take aliquot
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monicak

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Re: Exam Suggested Solutions
« Reply #128 on: June 12, 2008, 08:39:47 pm »
Thanks for typing up all the solutions and question 1. I've checked it again and I know what I stuffed up [stupid mistake]..  :-[ Hope I get at least 1 consequential mark from part c.. Would you be able to type up the text of SA question 8? I can't remember if that's the answer that I got  :(

Aba

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Re: Exam Suggested Solutions
« Reply #129 on: June 12, 2008, 08:39:58 pm »
i owned the absolute shites outa that exam!!!
hahah im sooo happy :D i was getting nervous b4 it...but wat for??

that was honestly a joke

Aba

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Re: Exam Suggested Solutions
« Reply #130 on: June 12, 2008, 08:41:20 pm »
wasnt there a double dilution for the manganese question, meaning the percentage of manganese was around 18%?????? thats wat ma friends says, i think he was right, cause his teacher said the same i think!



it was actually dissolve -> take aliquot -> dilute -> take aliquot


when u take an aliqout u r takin a certain amount of mole out, hence there is a dilution and an 'aliqout dilution' that need to be taken into account, ma friend said that, the only reason i think is cause his teacher said it
« Last Edit: June 12, 2008, 08:44:56 pm by Aba »

Aba

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Re: Exam Suggested Solutions
« Reply #131 on: June 12, 2008, 08:41:32 pm »
does ne1 reckon that for the systematic naming ull get the mark if u wrote 1-aminoethane???
coz thats wat i did:S stupid really

bucket

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Re: Exam Suggested Solutions
« Reply #132 on: June 12, 2008, 08:42:19 pm »
does ne1 reckon that for the systematic naming ull get the mark if u wrote 1-aminoethane???
coz thats wat i did:S stupid really

yes.
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infraredismybitch

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Re: Exam Suggested Solutions
« Reply #133 on: June 12, 2008, 08:46:07 pm »
seriously guys do you want to challange me to a chem off?
get back to me once uve figured this out yeh?

a substance with the formula 'C5H8O' is known to be a cyclic ketone, draw all possible structural isomers, and indicate if those, if any, can exist as stereoisomers.
piece of cake

vce01

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Re: Exam Suggested Solutions
« Reply #134 on: June 12, 2008, 08:48:59 pm »
lol how important are the hyphens when naming?

i think i wrote

2-methyl 5-chloroheptane

no hyphen between the methyl and 5, does it matter?
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