man0005's chemistry thread :)

[man0005]

Hey guys

my first question is for organic reactions, are the reactants/products generally going to be gases? if not, how can i tell?
e.g.
for an organic equation for hydrogen chloride

Any help is appreciated

[cltf]

Generally they will give some sort of indication like it is a "solution" thus liquid - for reactants - and if they don't specify you'll have to use general knowledge like, methane - butane are gaseous, and the rest on onwards are liquid. Then you can also like at the other reactant, chances are if it is reacting with a gas then the organic compound is gaseous too, eg Cl2.
HCl is typically aqueous, so your best bet is that the organic compound is probably going to be liquid or aqueous too.

[vea]

For typical compounds, you should be able to figure out what state it is.

eg. Alkanes with 1-5 carbons are gas
6-20 carbons are liquid
21-30 are waxy solids

If possible, also think about the dispersion forces or dipole-dipoles present.
eg. Ethanol is non-polar so it has a dipole and is stronger than the dispersion forces present in alkanes---> it is liquid.

[man0005]

ohh okay, thanks for that ^^
one more question, when adding atoms, i.e Chlorine, will it have a charge?
Like with a product of H
will it be H+ or just H?

[Water]

IF you have something like

C2H6 + Cl2 = C2H5CL + HCL

the H would have a H+ charge, if this is what your referring?

[Greatness]

C2H6 + Cl2 = C2H5 + HCL

Is that suppose to be C2H5Cl?
HCl would usually be a product - which is hydrochloric acid

[Water]

Sorry, mistype error on my part xD

[man0005]

yeah that was what i meant
anytime theres a question about substituting atoms, they will have charges when writing the reactions then?

[Greatness]

Well if you write them individually i.e. H+ and Cl- then yes you would have to, but if you wirte it as HCl then just state the state i.e. (aq)

[luken93]

Yeah you won't ever need to do it (I don't think) unless you are doing say an Acid-Base/Redox Reaction, in which case you may have:
HCl + H2O -> H3O+ + Cl-

[man0005]

how do you tell where the side chains are from the semi structural formula?
e.g (CH3) 2C=CHCH3

also in the textbook it had (CH3)2CHCH2CH3 as 1-methylbutane, isnt that just pentane?

[Greatness]

also in the textbook it had (CH3)2CHCH2CH3 as 1-methylbutane, isnt that just pentane?

yes thats pentane i finally got that cleared up lol. its a typo

also with the side chain i think that, that questoin means there is a side chain of the last carbon on the left. So it would probably look like CH3CH2CH=CHCH3?

[man0005]

so the brackets indicates a side chain?

[luken93]

also in the textbook it had (CH3)2CHCH2CH3 as 1-methylbutane, isnt that just pentane?

yes thats pentane i finally got that cleared up lol. its a typo

also with the side chain i think that, that questoin means there is a side chain of the last carbon on the left. So it would probably look like CH3CH2CH=CHCH3?

That isn't pentane, look at the end group, 2x CH3 groups:

      CH3
        |
 H - C - CH2 - CH3
        |
      CH3

It is indeed 2-Methyl Butane, not Pentane...

[Greatness]

that diagram makes it soooo mcuh easier >> Disregard what i said