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September 22, 2025, 09:39:00 pm

Author Topic: Help Required for Checkpoint question  (Read 592 times)  Share 

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ninbam1k

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Help Required for Checkpoint question
« on: April 13, 2011, 12:58:54 am »
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Question 2.
One molecule of butane (C4H10) would have a mass, in grams, of?

I looked at the answer and the explanation they used but I still don't understand how they got 58/( 6 x 10^23)

Help?

schnappy

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Re: Help Required for Checkpoint question
« Reply #1 on: April 13, 2011, 03:35:43 am »
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1 mol weighs 58 gram. In 1 mol, there are 6E23 molecules. So split the 58 into 6E23 molecules, you get 58/( 6 x 10^23).

Remember that the mol is just a heap of molecules, not some magical number.

VivaTequila

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Re: Help Required for Checkpoint question
« Reply #2 on: April 14, 2011, 09:28:02 pm »
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What schnappy said.

It's not asking for the mass of one mol, it's asking for the mass of a singular molecule, not a mole of molecules.

luffy

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Re: Help Required for Checkpoint question
« Reply #3 on: April 14, 2011, 10:18:57 pm »
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Question 2.
One molecule of butane (C4H10) would have a mass, in grams, of?

I looked at the answer and the explanation they used but I still don't understand how they got 58/( 6 x 10^23)

Help?

where n = no. of moles

Therefore, n = (no. of molecules)/(NA)

Therefore,







Hope I helped.
« Last Edit: April 14, 2011, 10:20:42 pm by luffy »