Banked Circular Motion Question

[Vincezor]

I was wondering if anyone has the full working out for the attached; I have no idea how to even start with this.

[xZero]

q4) Split the normal force into the horizontal and vertical component, the horizontal component = Nsin(35degrees). If there aren't any friction force acting down the slope then the maximum centripetal force is Nsin(35 degrees). Now F=ma, F=mv^2/r, sub in the values and find v

[Vincezor]

Thanks for the quick reply.

So if I'm not mistaken:

1. Horizontal/Vertical Component for normal force (Like the attached picture?)

So Vertical = and Horizontal =



and (Though why do we disregard this?)

so anyway:




v= 30.7ms^-1

Correct? :S

[xZero]

and (Though why do we disregard this?)

it should be and , note that if then the vertical component of N is greater than N, which doesn't make sense. It might be easier to work out N, then split it up so you don't get confused.

[Vincezor]

it should be and , note that if then the vertical component of N is greater than N, which doesn't make sense. It might be easier to work out N, then split it up so you don't get confused.

Could you explain this? I thought

Thus

[xZero]

In a normal downhill situation, N=mgcos(theta) right? Well its the same in this case, you work out N from mgcos(theta) then you split N up into 2 components where N is the hypotenuse

[schnappy]

There is a simple equation you can use, something like theta = inversetan(vv/g). I believe it might be a bit different to that... transpose it and you can get the velocity. I think everyone made the VCAA a bit mad last year when we got 3 marks for just substituting into a simple equation

[onur369]

I think it goes by squareroot(radius x gravity x tantheta) or it was v= squareroot(radius x gravity)

[xZero]

ROFL homemade equations are dodgy as... takes the fun out of solving an actual physics equation 

[onur369]

As if you classify them as homemade, if they work then there is no problem. They are all derived formulas.

[xZero]

I think of them as homemade equations is because half the people who are doing physics don't understand where they came from

VCE physics is turning into a "LOL I plug in numbers into this equation and solve for v" subject

[Thu Thu Train]

I think of them as homemade equations is because half the people who are doing physics don't understand where they came from

VCE physics is turning into a "LOL I plug in numbers into this equation and solve for v" subject

What do you mean turning into? It's been that way for years.

[Vincezor]

What do you mean turning into? It's been that way for years.

Yeah, it's pretty sad... It doesn't feel as satisfying getting a good score in practice exams when compared to chemistry

I think it goes by squareroot(radius x gravity x tantheta) or it was v= squareroot(radius x gravity)

I believe it is something like..


"Max speed at top of a crest without car leaving ground"
N=0


Rearrange

?

[onur369]

Yes thats correct