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October 18, 2025, 10:50:19 am

Author Topic: Concentration vs Time Graphs Question  (Read 698 times)  Share 

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Vincezor

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Concentration vs Time Graphs Question
« on: July 05, 2011, 01:39:59 pm »
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[IMG]http://img16.imageshack.us/img16/9252/concvtime.png[/img]

Basically, we have to account for what occurred.

For the one on the left, I initially thought it was simply just the same as the one on the right, however I then realised the one on the right had a bit of a slant, which indicated that the temperature decreases (Is this correct? or is a catalyst added?).

I have no idea what occurs on the left diagram, I'm going to take an educated guess and say it is just a temperature decrease.

Sorry, I may be wrong on one or both accounts :P

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luken93

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Re: Concentration vs Time Graphs Question
« Reply #1 on: July 05, 2011, 01:54:48 pm »
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So the one on the left, you are at equilibrium until you hit the arrow. At this point, c(Product) increases, and c(Reactants) decreases =>  K increases
This could be a range of things, but probably decreasing the volume or as you say, decreasing the temp.

As for the second, I'd say the equilibrium hasn't been reached yet, as the concentrations aren't constant (although I've never seen one like this). At the arrow, they do the same thing as the first graph,
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Vincezor

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Re: Concentration vs Time Graphs Question
« Reply #2 on: July 08, 2011, 04:23:44 pm »
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Cheers luken :)
2010: Systems Engineering 44            

2011: Specialist Mathematics 37 | Mathematical Methods (CAS) 43 | Physics 39 | Chemistry 42 | English 41

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