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June 13, 2026, 06:20:04 am

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Rosie

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help with questions
« on: August 26, 2008, 05:29:43 pm »
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Just a few questions that I have  no clue about on a prac that I'm working on:


What would be the effect on the calibration factor obtained from this experiment of using 50ml of water instead of 100ml of water to calibrate the calorimeter?

In future experiments what volume of solution should you place in the calorimeter to meausure the enthalpy changes of chemical reactions?

Energy is neither created nor destroyed in a chemical reaction. Explain where the energy released (or absorbed) by the reactions comes from (or goes to).

thanks for that
« Last Edit: August 28, 2008, 07:33:58 pm by Rosie »

Collin Li

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Re: help with calorimetry prac
« Reply #1 on: August 26, 2008, 06:11:19 pm »
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Energy is stored in chemical bonds as "chemical potential" energy. Under a chemical reaction, these bonds are rearranged, and hence there is a change in "chemical potential" energy. The difference is released (or absorbed) as heat. This is consistent with the conservation of energy - as the change in temperature (measured change in heat) corresponds to an equal and opposite change in "chemical potential," so the net change in energy is zero.

Collin Li

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Re: help with calorimetry prac
« Reply #2 on: August 26, 2008, 06:16:09 pm »
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What would be the effect on the calibration factor obtained from this experiment of using 50ml of water instead of 100ml of water to calibrate the calorimeter?

In future experiments what volume of solution should you place in the calorimeter to meausure the enthalpy changes of chemical reactions?

The CF would decrease (measured in the units of energy per change in temperature). Less volume would mean there is less energy required to raise the temperature of the solution.

You should use the exact some volume of solution in the calorimeter as when you calibrated it (i.e: calibration factor obtained with 100mL in calorimeter means you should have 100mL in the calorimeter when measuring enthalpy changes of a reaction)

Rosie

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Re: help with calorimetry prac
« Reply #3 on: August 26, 2008, 07:20:30 pm »
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relating to this prac...............

I have to calculate the heat of reaction and give its sign for each equation between:

Mg and HCl
Now i have weighed out 0.22g of Mg and the energy change was found to be 4806J.
I'm pretty sure that to calculate the heat of reaction you divide the energy change by the mole of the limiting regeant, is that right?


Also, Sketch the temperature against time graph that you would expect to obtain for:
a poorly insulated calorimeter
a well insulated calorimeter

thanks again
« Last Edit: August 26, 2008, 07:50:43 pm by Rosie »

lauzy358

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Re: help with calorimetry prac
« Reply #4 on: August 27, 2008, 02:05:21 pm »
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I've got the write up for our calorimetry prac on Friday..we calibrated last week & need to the reactions and the rest of it.
So I'll try and help xp
I think we're doing the same prac, too!

I'm pretty sure that to calculate the heat of reaction you divide the energy change by the mole of the limiting regeant, is that right?

Yerp, I think it is. Then you'd get an answer in J/mol (since your energy change was in J). When you write the thermochemical equation though you have to be careful of the mole ratio thing.
Since it's
Mg + 2HCl --> H2 + MgCl2
You don't have a problem though ('cause the ratio for Mg is 1)
& sry my language is a bit off here...
could someone explain this better? or clarify...? ^^"

Sketch the temperature against time graph that you would expect to obtain for:
a poorly insulated calorimeter
a well insulated calorimeter

A well insulated calorimeter's graph would look like this:
http://www.acornusers.org/education/Thesis/Images/BombCalorimeter/Pic1.gif

If you have the Nelson Chemistry book I found they had good graphs of well insulated vs. poorly insulated.

Although if you've calibrated your calorimeter, graph its time vs. temperature... if it doesn't result in a graph like that one^ it's not well insulated =]
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Rosie

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Re: help with calorimetry prac
« Reply #5 on: August 27, 2008, 02:44:02 pm »
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thanks for that



« Last Edit: August 28, 2008, 07:41:00 pm by Rosie »

Rosie

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Re: help with questions
« Reply #6 on: August 28, 2008, 07:41:23 pm »
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another question
Q. A lead-acid battery uses 50g of lead to provide the electrical energy needed to start a typical car. Calculate the mass of lead oxide consumed at the positive electrode and the total mass of lead sulfate produced in the battery while starting the car.

thanks

Ken

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Re: help with questions
« Reply #7 on: August 28, 2008, 07:45:53 pm »
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a basic stoichiometry question, u need the overall equation.
Find the moles of lead first and then apply mole ratios.

Rosie

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Re: help with questions
« Reply #8 on: August 29, 2008, 07:35:05 am »
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yes and this is what i had trouble doing. How do i write the overall equation. Are there two half equations?

Collin Li

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Re: help with questions
« Reply #9 on: August 29, 2008, 07:49:44 am »
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The overall equation for a lead-acid battery should be in your book. Ultimately the lead-acid battery features lead in oxidation states 0 and +4, then a redox reaction happening in between them to achieve a compound of lead with an oxidation state of +2.

is the one in oxidation state +4. To get to +2, it requires 2 electrons.
is the one in oxidation state 0. To get to +2, it needs to lose 2 electrons.

You should see that there is clearly a 1:1 molar relationship between lead and lead (IV) oxide because they both need to gain/lose 2 electrons each.







Now, to find the mass of lead sulphate:

It should be clear that the reaction will look something like:



This is unbalanced, and clearly missing some reactants and products, but it will do for our purposes. What I have done is basically an elemental balance: I know that my reaction only has two sources of lead - the lead (IV) oxide and the pure lead. On the products, the only place where lead is produced is in the lead sulphate.

In non-nuclear chemistry, the elements at the beginning balance with the elements at the end, so therefore there must be 2 times as much lead sulphate than there was lead (IV) oxide or pure lead (because they both combined in a ratio to form moles of lead sulphate).



A clearer way, and more explicit way of thinking about the elemental balance is this:



This will give you the same result as above, since





Learning how to utilise the elemental balance to save yourself from writing a full equation is also very helpful sometimes. I used it in my actual exam (VCAA Chemistry 2006) for Unit 3.

By the way, we could have looked up this equation from our textbook, but it's more fun to deduce things with minimal information. It's also useful if you're actually supposed to know this equation (I'm not sure), you can just remember the bare minimum, and build the rest up as you go along, like I did here.
« Last Edit: August 29, 2008, 08:02:53 am by coblin »

Mao

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Re: help with questions
« Reply #10 on: August 29, 2008, 09:26:53 am »
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The two half equations are:





overall:

« Last Edit: August 29, 2008, 09:29:37 am by Mao »
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Rosie

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Re: help with questions
« Reply #11 on: August 31, 2008, 10:27:50 am »
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thanks everyone

more questions

Q. Regarding the equation:
CO + 0.5O2 ----> CO2; delta H=-283kJ mol

a. What has the greater heat content: 1 mol of CO and 0.5 mol of O2, or 1 mol of CO2.

b. Write the value of delta H for the reactions:
i. 2CO + O2 ----> 2CO2
ii. 2CO2 -----> 2CO + O2


Q. Regarding the equation:
2C4H10 + 13O2 -----> 8CO2 + 10H2O; delta H= -5772KJ mol

Calculate the volume of butane, measured at 15 degrees and 108Kpa, that must be burnt to yield 1.00kJ of energy.   
 ;D

orangez

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Re: help with questions
« Reply #12 on: August 31, 2008, 04:42:44 pm »
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a) 1 mol of CO and 0.5 mol of O2  (it's an exothermic reaction, so look at its energy profile)

b(i) delta H = 2 * -283 kJ/mol = -566 kJ/mol  (see how the coefficients are doubled?)
 (ii) delta H = 566 kJ/mol  (reaction is reversed)



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Mao

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Re: help with questions
« Reply #13 on: August 31, 2008, 04:49:39 pm »
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2:

energy released per kJ of butane: kJ/mol



using pV=nRT

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Rosie

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Re: help with questions
« Reply #14 on: September 01, 2008, 04:59:55 pm »
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thanks guys

more troubling questions

Q. An oxy-acetylene welding torch uses ethyne at the rate of 500ml per minute, measured at STP. The reaction is:
2C2H2 + 5O2 -----> 4CO2 + 2H2O

a. What is the heat of combustion of ethyne in kJ mol-1 and kJ g-1?
b. Calculate the rate of energy production by the torch in kJ per minute?

I don't know how to convert the units!


Q. A calorimeter is used to measure energy changes that occur during chemical reactions.
a. Why should a calorimeter be well insulated?
b. Why is it necessary to calibrate a calorimeter?
c. The combustion of a 3.00g piece of wood in a bomb calorimeter results in an observed temperature rise of 1.6 degrees. The calibration factor of the calorimeter was 30.0kJ degrees C-1. Calculate the heat of combustion of the wood.