Reaction Rates

[Pandemonium]

increasing the rate of the reaction will increase the rate at which the system reaches equilibrium.
so high temperature and low flow rate. (low flow rate maximises the contact time with the catalyst, making the reaction faster)

[Mao]

yeah, to achieve equilibrium [without any consideration of yield] would want the max
Temperature
Pressure
Flow rate over catalyst
surface area

etc.

[bec]

Wait, you contradicted each other - max or min flow rate?

[Pandemonium]

minimum flow rate.

[Mao]

that seems counter-intuitive. catalysts give alternative reaction pathways, and I'd assume that is also collision based. Hence to maximise the number of collisions, we want maximum flow rate.

[imagine if you had it at minimum flow rate, like 1 mL/hour, no matter how good the catalyst is, the production is going to be very slow]

[bec]

It's minimum (says in the answers)
I agree, it goes against what seems logical to me too. But VCAA's word, goes.
Can someone explain this low flow thing? Is it just that with a low flow rate, the particles are in contact with the catalyst for longer? (See, to me, it would make more sense to have MORE particles having contact with the catalyst...in high flow...but anway...)

[Pandemonium]

think about it like this.

if the gas require 0.5 seconds of flow time in order to achieve 99% conversion, and you flow for 0.4 seconds, you might get something like 90%.

[Mao]

think about it like this.

if the gas require 0.5 seconds of flow time in order to achieve 99% conversion, and you flow for 0.4 seconds, you might get something like 90%.

that is true, but if you slow the flow rate to say 30 minutes, then that will be really inefficient, even though it is "minimum" flow rate

[Pandemonium]

think about it like this.

if the gas require 0.5 seconds of flow time in order to achieve 99% conversion, and you flow for 0.4 seconds, you might get something like 90%.

that is true, but if you slow the flow rate to say 30 minutes, then that will be really inefficient, even though it is "minimum" flow rate

w

think about it like this.

if the gas require 0.5 seconds of flow time in order to achieve 99% conversion, and you flow for 0.4 seconds, you might get something like 90%.

that is true, but if you slow the flow rate to say 30 minutes, then that will be really inefficient, even though it is "minimum" flow rate

well, we don't really need hyperbole.

[Collin Li]

All the question really means to ask is: what will maximise the rate of reaction? Saying "achieving equilibrum most rapidly" is a trickier way of saying the same thing.

That will be a high temperature and a low flow rate (allows the catalyst to be active more readily).