hards methods i mean specialist :D questions

[shinny]

That's the definition of i.


EDIT: Oh, you meant as in that way. And as for your first step, just remember that any polynomial to the power of n has n number of solutions (fundamental theorem of algebra), so you should know that stating something like what you had would add invalid solutions in some way.

[Glockmeister]

Yeah, we started 2 weeks of transition yesterday. Only half my GMA class had the guts to tackle specialist.

half lol what the hell! Only 6 kids are doing it in our school and i didn't do general advanced maths so i'm starting fresh with spesh. Seems good so far.

also i got another question to check if it is right: To damo this is q1h of chapter 3A

Using the imaginary number i, write down expression for the following


x² = -36/25
x² = -1 x 36/25
x² = i² x 36/25
x = (plusminus)
x = (plusminus) i x 6/5



EDIT: change 35>25

Ok with this, yes and no. You've actually kinda cheated because you have used an equation by letting the expression equal something when the question asked for an expression.

EDIT: Obviously shin has dived in with the answer.

[hard]

Your first step is incorrect. By stating , you're adding another answer in which is why you have the

Try this:

but were did you get

 

ya lol got that

[Glockmeister]

oh btw hard it would have been funny if you got rid of the s in hard in the topic title.

[hard]

oh btw hard it would have been funny if you got rid of the s in hard in the topic title.

:p haha i thought the same thing right before i clicked post

[danieltennis]

oh btw hard it would have been funny if you got rid of the s in hard in the topic title.

:p haha i thought the same thing right before i clicked post

HARD, did u do GMA this year?

[shinny]

...i didn't do general advanced maths so i'm starting fresh with spesh...

etcetc.

[Flaming_Arrow]

i did it last year but don't remember anything

[hard]

okay the question asks

evaluate:

R_e(-5+4i) and I_m(1-6i)

[gfb]

okay the question asks

evaluate:

R_e(-5+4i) and I_m(1-6i)

Real = -5
Imaginary = -6   

Not sure of what the Q asks

[hard]

ahkai i was thinking that they were asking for more

[ell]

Another tip you might find useful with complex numbers (you might already know this but I'll post it anyway):

When you have something like , an easy way to simplify it is to divide the power by 4, and whatever the remainder is becomes the new power (in this case, the remainder is 2 and so: )

[hard]

Another tip you might find useful with complex numbers (you might already know this but I'll post it anyway):

When you have something like , an easy way to simplify it is to divide the power by 4, and whatever the remainder is becomes the new power (in this case, the remainder is 2 and so: )

thanks for that but i usually just put (i^2) and then put the remaining value outside the brackets needed for 2 to be multiplied by that number to equal in this case 38. This way i cancel the i^2 out and then have -1^16 in this case.but thanks again

[NE2000]

Ahh...so the baton passes on to 2009 spesh students. I've just started with the graphs in chapter one, pretty cool stuff so far...

[Mao]

Your first step is incorrect. By stating , you're adding another answer in which is why you have the

Try this:

I would be very careful factoring that square root of -1



as you can see, it's not exactly the 'right' thing to do in surds

what 'should' be done is