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October 12, 2025, 05:47:38 am

Author Topic: help; i really need a tutor  (Read 8969 times)  Share 

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Collin Li

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Re: help; i really need a tutor
« Reply #15 on: December 04, 2008, 08:37:10 pm »
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My only complaint about coblin is that he'll probably mark your work in hot pink.


...not that it's a bad thing :P

What? No I don't.

khalil

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Re: help; i really need a tutor
« Reply #16 on: December 12, 2008, 03:53:19 pm »
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Hey can someone help me with this question:
Draw the stuctural formula of 1,2,3-trimethylbutan-1-ol
the answers have 2 OH's .....dont know if they made a mistake
btw the question is in pg.136 Q8 d in the jacaranda textbook
thanks

khalil

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Re: help; i really need a tutor
« Reply #17 on: December 12, 2008, 05:22:08 pm »
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Also,
An oxide of iron contains 21.33% oxygen by mass. Find the empirical formula. Ans: Fe(2)O(3)

A compound X is used in ceramic work in the form of its hemihydrate X..5H(2)O which, when mixed with water, gives a solid dihydride X.2H(2)O. If 2.9g of hemihydrate yeilds 3.44g of dihydride, what is the molar mass of the dihydrate X.2H(2)O     Ans, 136

thanks

Collin Li

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Re: help; i really need a tutor
« Reply #18 on: December 12, 2008, 09:46:17 pm »
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Hey can someone help me with this question:
Draw the stuctural formula of 1,2,3-trimethylbutan-1-ol
the answers have 2 OH's .....dont know if they made a mistake
btw the question is in pg.136 Q8 d in the jacaranda textbook
thanks

That's a pretty weird question already, since that molecule when drawn out should really be named by "pent-" rather than "but-". There are 5 carbons in the longest chain, since there is a methyl group off the end.

Also,
An oxide of iron contains 21.33% oxygen by mass. Find the empirical formula. Ans: Fe(2)O(3)

1 gram of the iron oxide has 0.2133 g of oxygen and 0.7867 g of iron. Divide by their molar masses to reveal:




Note: the fact we chose "1 gram" makes no difference, because we're interested in the ratio between: for the empirical formula, which will be the same regardless of how much grams we worked with to begin with (I arbitrarily chose 1 gram - you could choose 100 if you like).

Anyway: (roughly, is good enough)

Hence is the empirical formula. I disagree with the answers.

A compound X is used in ceramic work in the form of its hemihydrate X..5H(2)O which, when mixed with water, gives a solid dihydride X.2H(2)O. If 2.9g of hemihydrate yeilds 3.44g of dihydride, what is the molar mass of the dihydrate X.2H(2)O     Ans, 136





Since the must balance on both sides of the equation , then they are equimolar:



Since









Once again, the answer is wrong, because we're not done: we want

Crap book.
« Last Edit: December 12, 2008, 09:51:26 pm by coblin »

khalil

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Re: help; i really need a tutor
« Reply #19 on: December 13, 2008, 03:14:24 pm »
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Thanks Coblin
If a compound is 0.5H(2)O does that mean there is 1 hydrogen? (.5x2)

Mao

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Re: help; i really need a tutor
« Reply #20 on: December 13, 2008, 04:57:56 pm »
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I'd think it'll be
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Collin Li

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Re: help; i really need a tutor
« Reply #21 on: December 13, 2008, 07:52:38 pm »
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Thanks Coblin
If a compound is 0.5H(2)O does that mean there is 1 hydrogen? (.5x2)

Yes.

khalil

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Re: help; i really need a tutor
« Reply #22 on: December 13, 2008, 07:56:08 pm »
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Thanks Coblin
If a compound is 0.5H(2)O does that mean there is 1 hydrogen? (.5x2)

Yes.

Is CuSO(4).5H(2)O the same as CuSO(4)H(10)O(2)?

Collin Li

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Re: help; i really need a tutor
« Reply #23 on: December 13, 2008, 08:01:32 pm »
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Yeah kinda, I think you mean (put all the oxygens together).

The reason why they write it like is to indicate something about its structure, but you don't need to know about that stuff in VCE.

dekoyl

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Re: help; i really need a tutor
« Reply #24 on: December 13, 2008, 08:38:15 pm »
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Thanks Coblin
If a compound is 0.5H(2)O does that mean there is 1 hydrogen? (.5x2)

Yes.
So there's one hydrogen and.. half an oxygen? Or does it become ?

Collin Li

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Re: help; i really need a tutor
« Reply #25 on: December 13, 2008, 08:40:33 pm »
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Yeah, it's half an oxygen. But that's not indicative of molecular structure, that's just how the compound is written in this chemical equation. No need to try to make sense of it.

You could similarly write something like: in a chemical equation too.
« Last Edit: December 13, 2008, 08:45:07 pm by coblin »

dekoyl

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Re: help; i really need a tutor
« Reply #26 on: December 13, 2008, 08:43:49 pm »
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Ah okay thanks Coblin.

I just thought it had to be a whole number (so to multiply all the species by 2 to make it

khalil

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Re: help; i really need a tutor
« Reply #27 on: December 20, 2008, 08:51:01 pm »
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someone help please
0.148g of a metal carbonate exactly reacts with 20ml of 0.1 M HCL. The formula of the metal carbonate is most likely be:
A. Li(2)CO(3)
B. Na(2)C0(3)
c. MgC0(3)
D. SrC0(3)

Mao

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Re: help; i really need a tutor
« Reply #28 on: December 20, 2008, 09:51:01 pm »
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write an equation showing the reaction between carbonate and H+, and use the mole ratio to find the number of moles of metal carbonate.

and then use , and see which option matches up.
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khalil

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Re: help; i really need a tutor
« Reply #29 on: December 21, 2008, 10:52:22 am »
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yer thats what the answers state...but i didnt get it!