hielly's maths thread

[Over9000]

So, you can keep the answer I gave you, or if you wish to get the exact answer, instead of suing 150796, use as total volume

[Over9000]

Extended response is about as hard as it gets. It's the hardest questions you could get, dont worry if you cant do all of them, you should ask your teacher for help, or just post the questions on VN forums

[shinny]

Extended response is about as hard as it gets. It's the hardest questions you could get, dont worry if you cant do all of them, you should ask your teacher for help, or just post the questions on VN forums

Actually I think the best way to learn how to do extended response is to actually spend a lot of time systematically working your way through it. The majority of extended response questions are easy once you know the methods and end up on par with short answer questions, just with fuglier numbers. What I think people need to do is actually take the courage to work on it themselves without time constraints and develop their problem solving skills. Learning the methods from others won't tend to help develop these skills for the exam unless you strike it lucky and you end up with the exact same question again. However, knowing VCAA, this is pretty much impossible to happen. There WILL be something new on the exam, and for cases like these, you will need to build up your independence in learning to approach these sorts of questions.

[Over9000]

Extended response is about as hard as it gets. It's the hardest questions you could get, dont worry if you cant do all of them, you should ask your teacher for help, or just post the questions on VN forums

Actually I think the best way to learn how to do extended response is to actually spend a lot of time systematically working your way through it. The majority of extended response questions are easy once you know the methods and end up on par with short answer questions, just with fuglier numbers. What I think people need to do is actually take the courage to work on it themselves without time constraints and develop their problem solving skills. Learning the methods from others won't tend to help develop these skills for the exam unless you strike it lucky and you end up with the exact same question again. However, knowing VCAA, this is pretty much impossible to happen. There WILL be something new on the exam, and for cases like these, you will need to build up your independence in learning to approach these sorts of questions.

Shinny is right, however, I think to start off, you should get help from friends or teachers as it can be daunting to do on your own, then when you are a little more comfortable with doing extended response questions, then start doing them your own unique way by yourself.

[Hielly]

yerh thanks. the bad thing is that our teacher doesn't give us time to do chapter reviews in class. when we finish the questions from 1 chapter he tells us to do the chapter review at home. im struggling with the extended-reponse questions. i might purchase the solution supplements but im not going to use it all the time, just for emergencies when i'm extremely stuck on a question

[shinny]

If you're going to use solutions, I suggest annotating 'thought processes' on them as you read them. This can still be of use and will help you realise the systematic ways to approach questions, and the little hints you need to look out for. Other than that, perhaps you could request thought processes to be annotated when you ask for help on VN. I've done this a few times I think and I'm sure others (or myself if I have the time) will be glad to do these in future.

[Over9000]

yerh thanks. the bad thing is that our teacher doesn't give us time to do chapter reviews in class. when we finish the questions from 1 chapter he tells us to do the chapter review at home. im struggling with the extended-reponse questions. i might purchase the solution supplements but im not going to use it all the time, just for emergencies when i'm extremely stuck on a question

yerh thanks. the bad thing is that our teacher doesn't give us time to do chapter reviews in class. when we finish the questions from 1 chapter he tells us to do the chapter review at home. im struggling with the extended-reponse questions. i might purchase the solution supplements but im not going to use it all the time, just for emergencies when i'm extremely stuck on a question

Doesn't your teacher allow you to see him at lunch, before or after school if you have any questions. If not, then you can just post your questions up here, I had to ask tons of questions about my practice spesh sac and true tears helped me with all my questions, so feel free to post questions you have trouble with. I know I will try and answer them.

[Hielly]

yerh thanks over9000! hey just wondering if you did all the extended questions in year 11 for maths?

[Over9000]

No, didn't do many, which I regret, I probably couldve done most but I was lazy. Even now it's a struggle for me to find the time for extended response, probably because specialist maths takes up so much of my time.  8-)

[Hielly]

TOPIC: PROBLEM SOLVING SETS

please view attachmennt
stuck on q 8 and 10

[Over9000]

Heres the answer to q.10
its a bit messy

[Over9000]

Heres some solutions from the booklet

[Hielly]

okay this is circle theorems
If AB is a chord and P is a point on AB such that AP = 8 cm, PB = 5 cm and P is 3 cm
from the centre of the circle, find the radius.

thanks

The answer is 7cm

[Mao]

(cosine rule)

drawing the picture out, we construct two more lines: OA and OB, both are radii of the circle. In this case, we have three triangles, OAP, OBP and OAB.

OAP:

OBP:

acknowledging cosine's symmetry, , we have two simultaneous equations

  [1]

  [2]

multiplying [2] by and adding to [1]:

[TrueTears]

notice is a isosceles and OH is perpendicular to AB



ok so AB = 13 (8+5)

now HP = HB - PB = (notice H is the midpoint of AB)

now this yields HP = 1.5

and OP = 3

using Pythagoras yields solving for OH yields

so then looking at

(OB is radius)



solving for OB yields OB = -7 or 7

negative cant exist so OB = 7