Solve 2sin(3x-pi/4) = -1 over (-pi, pi]
Im having troubles with the domain change, thanks! 
Assuming you mean solving for x
Since

, naturally

Now, solving,
=-1)
=-\frac{1}{2})
=-\frac{17\pi}{6},-\frac{13pi}{6},-\frac{5\pi}{6},-\frac{\pi}{6},\frac{7\pi}{6},\frac{11\pi}{6})
Then, rearranging -

and finally

With the domain, I always like to think of it as applying the same operations to the domain as you do to the variable.
Consider this scenario, we are playing a "guessing game". I have to pick a number, and you have to guess what that number is.
I have to pick a random number (which we will call A) that lies between 0 and 10.

(Don't rant about sets and integers - this is purely for demonstrative purposes)
Ok, now, my directions are - first - to multiply the number by 2.
If you were to guess my number (final number) at this point, would you agree that you would guess any number between 0 and 20? If I chose the smallest number 0, and multiplied this by 2, I would still have 0. But if I chose 10 to start with, this would now become 20. So, therefore

Now, If you told me to subtract 3 from this number (already multiplied by 2). The possible numbers now be

. If I started with 0, multiply it by 2 and subtract 3 - that's -3. If i start with 10, multiply it by 2 and subtract 3 - that's 17.
Going back to the question - If you know that x lies between -pi and pi, then 3x lies between -3pi and 3pi, and 3x-pi/4 lies between -3pi-pi/4 and 3pi-pi/4!
I hope this analogy of sorts wasn't too convoluted and pointless -I have a tendency to do that

My teacher HEAVILY stresses it's D though :/ Why would this be so?
Hahahha I can't really explain to you why an incorrect answer is correct. (I don't do debating)