VCE Methods Question Thread!

[qwerty101]

help plz

[IndefatigableLover]

In regards to application questions, if they don't specify what decimal place to round off to, and we get something like 12.99 or 15.49 can we automatically round off or not? Thanks

If they don't specify the decimal place to round to then you always keep your answer as an exact value answer.

[cosine]

If they don't specify the decimal place to round to then you always keep your answer as an exact value answer.

No i mean straight off the calculator, we get a decimal answer with no exact value?

[Redoxify]

f(x)= sin pix/4             g(x)= -root(3)cos pix/4
find the two smallest possible values for which f(x) = g(x)

[faso]

No i mean straight off the calculator, we get a decimal answer with no exact value?

Change your settings. Take it off approximate and make it exact.

[cosine]

f(x)= sin pix/4             g(x)= -root(3)cos pix/4
find the two smallest possible values for which f(x) = g(x)

So we have

[cosine]

Is this possible? It's a tech-free question:

Determine the maximal domain and range of

I know the domain is

But how can we find the range?

[StupidProdigy]

Is this possible? It's a tech-free question:

Determine the maximal domain and range of

I know the domain is

But how can we find the range?

Think about the asymptotic behaviour, does y approach when you sub in a really big x value? Also realise the reflection in the x axis will flip the range around meaning it will be from negative infinity to the asymptote. Hope that helps

[cosine]

Think about the asymptotic behaviour, does y approach when you sub in a really big x value? Also realise the reflection in the x axis will flip the range around meaning it will be from negative infinity to the asymptote. Hope that helps

Correct answer is -5

Given
Find the average rate of change between [1, 5]?

[StupidProdigy]

Correct answer is -5

Given
Find the average rate of change between [1, 5]?

No it's not, that's the y-int. Is there a domain restriction?

[cosine]

Correct answer is -5

Given
Find the average rate of change between [1, 5]?

Bump

[Redoxify]

Correct answer is -5

Given
Find the average rate of change between [1, 5]?

a(5) - a(1)/5-1
very simply because you can  picture the equation given as y= (h+3)^2 + 500 so when you sub in x you get y,
hence you can do y2-y1/x2-x1,
hope this helps

[cosine]

a(5) - a(1)/5-1
very simply because you can  picture the equation given as y= (h+3)^2 + 500 so when you sub in x you get y,
hence you can do y2-y1/x2-x1,
hope this helps

So you're saying that average rate of change is from a value to another, whereas the instantaneous rate of change is at one particular point of the curve?

[Redoxify]

So you're saying that average rate of change is from a value to another, whereas the instantaneous rate of change is at one particular point of the curve?

exactly

[cosine]

Why is it that when we find the equation of tangents, we first find the gradient at the x-value, then find the corresponding y-value and substitute them into y=mx+c?