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June 16, 2024, 08:16:55 pm

Author Topic: VCE Methods Question Thread!  (Read 4891783 times)  Share 

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Maz

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Re: VCE Methods Question Thread!
« Reply #12810 on: December 08, 2015, 05:07:30 pm »
0
Hey can someone help me with this one- its differentiation...
An oil slick is approximately circular of radius 'r' m and thickness 5cm. Find an expression for the volume of oil in the slick in m^3.
Use differentiation to determine the approximate increase in the radius if a further 1m^3 of oil leaks into the slick when the radius in 20m, the thickness remaining at 5cm?

Thanks in advance :)
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lzxnl

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Re: VCE Methods Question Thread!
« Reply #12811 on: December 08, 2015, 06:47:11 pm »
0
Hey can someone help me with this one- its differentiation...
An oil slick is approximately circular of radius 'r' m and thickness 5cm. Find an expression for the volume of oil in the slick in m^3.
Use differentiation to determine the approximate increase in the radius if a further 1m^3 of oil leaks into the slick when the radius in 20m, the thickness remaining at 5cm?

Thanks in advance :)

When you have these questions, if it says 'approximate increase', that should make you think 'related rates'.
So to do so, you want to relate the radius to the volume.
Well, volume of the oil slick is pi r^2 h
dV = 2pi*r*h dr
To use linear approximation, you literally plug in dV = 1 m^3, r = 20 m, h = 0.05 m and solve for dr

Your teachers won't like you doing that so technically you should write delta V is roughly dV/dr * delta r, but I'm a physicist and we do these things all the time :P
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Maz

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Re: VCE Methods Question Thread!
« Reply #12812 on: December 08, 2015, 07:32:39 pm »
0
thankyou :)
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jimsmowing

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Re: VCE Methods Question Thread!
« Reply #12813 on: December 08, 2015, 10:13:14 pm »
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Someone HELP!!  :-[

"Let 'a' be a positive number, let f: [2,∞)→R, f(x)=a−x and let g:(−∞,1]→R, g(x) = x^2 + a. Find all values of 'a' for which both f ◦ g and g ◦ f exist."

MightyBeh

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Re: VCE Methods Question Thread!
« Reply #12814 on: December 08, 2015, 10:55:13 pm »
+3
Someone HELP!!  :-[

"Let 'a' be a positive number, let f: [2,∞)→R, f(x)=a−x and let g:(−∞,1]→R, g(x) = x^2 + a. Find all values of 'a' for which both f ◦ g and g ◦ f exist."

Haha, this one's from Cambridge isn't it? I vaguely recall messing it up ::)

Key to this one if knowing that for fog to be defined, ran g must be a subset of dom f. Likewise for gof, ran f must be a subset of dom g. If that doesn't help, working's in the spoiler.

Spoiler

Because this is a simple parabola, the minimum will be at a and, while the domain is restricted on one side, it will still go up infinitely high on the left side.

f is a bit more complicated, it's a straight line which usually has a range of R. However because the domain is restricted we have to sub in the upper and lower values to find the range.


when working with infinity, any other parts of an expression are pretty useless so we just throw out the a.


Let's start with defining fog - for fog to exist, ran g ⊆ dom f, which means:

So a must be equal to or greater than 2.

Now gof:

we're all good on the LHS (I'm using the term loosely ::) ), but for ran f to be a subset of dom g, (a - 2) must be less than 1.



Putting what we know together:
, or another accepted notation;
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jimsmowing

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Re: VCE Methods Question Thread!
« Reply #12815 on: December 08, 2015, 11:19:42 pm »
+2
Haha, this one's from Cambridge isn't it? I vaguely recall messing it up ::)

Key to this one if knowing that for fog to be defined, ran g must be a subset of dom f. Likewise for gof, ran f must be a subset of dom g. If that doesn't help, working's in the spoiler.

Spoiler

Because this is a simple parabola, the minimum will be at a and, while the domain is restricted on one side, it will still go up infinitely high on the left side.

f is a bit more complicated, it's a straight line which usually has a range of R. However because the domain is restricted we have to sub in the upper and lower values to find the range.


when working with infinity, any other parts of an expression are pretty useless so we just throw out the a.


Let's start with defining fog - for fog to exist, ran g ⊆ dom f, which means:

So a must be equal to or greater than 2.

Now gof:

we're all good on the LHS (I'm using the term loosely ::) ), but for ran f to be a subset of dom g, (a - 2) must be less than 1.



Putting what we know together:
, or another accepted notation;

Thanks m8, you're a legend  ;D

Adequace

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Re: VCE Methods Question Thread!
« Reply #12816 on: December 09, 2015, 01:58:34 pm »
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I'm encountering problems when trying to solve literal equations with my CAS. I'm using the ClassPad and when I tried solving x for ax+b=cx+d, I just get an incorrect argument error?

I just use the solve(...,x) function.

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Re: VCE Methods Question Thread!
« Reply #12817 on: December 09, 2015, 02:02:01 pm »
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I'm encountering problems when trying to solve literal equations with my CAS. I'm using the ClassPad and when I tried solving x for ax+b=cx+d, I just get an incorrect argument error?

I just use the solve(...,x) function.

Try typing in a*x as opposed to ax.

Otherwise I'm not sure, I don't use a ClassPad. Don't forget to try turning it on and off again, and resetting it if you can. :P

Adequace

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Re: VCE Methods Question Thread!
« Reply #12818 on: December 09, 2015, 02:23:58 pm »
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Try typing in a*x as opposed to ax.

Otherwise I'm not sure, I don't use a ClassPad. Don't forget to try turning it on and off again, and resetting it if you can. :P
I still get the same error unfortunately, damn.

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Re: VCE Methods Question Thread!
« Reply #12819 on: December 09, 2015, 03:44:57 pm »
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I still get the same error unfortunately, damn.
Are you using the letters from the VAR tab? (In the image, I didn't use the VAR tab at first, then using it gave me the correct answer.)

Adequace

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Re: VCE Methods Question Thread!
« Reply #12820 on: December 09, 2015, 03:48:08 pm »
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Are you using the letters from the VAR tab? (In the image, I didn't use the VAR tab at first, then using it gave me the correct answer.)
Yeah, I've been using the VAR table for the letters apart from x. I'll try using the x from the VAR tab and see if it it works.

Adequace

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Re: VCE Methods Question Thread!
« Reply #12821 on: December 09, 2015, 05:01:57 pm »
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Yeah, I've been using the VAR table for the letters apart from x. I'll try using the x from the VAR tab and see if it it works.
I still get the same error...it must be my CAS.

Edit: I resetted my CAS and now it works. This made me incredibly happy hilariously..
« Last Edit: December 09, 2015, 05:16:08 pm by Adequace »

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Re: VCE Methods Question Thread!
« Reply #12822 on: December 09, 2015, 05:10:09 pm »
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I still get the same error...it must be my CAS.
Try typing in a*x as opposed to ax.

Otherwise I'm not sure, I don't use a ClassPad. Don't forget to try turning it on and off again, and resetting it if you can. :P
Did you do c*x in addition to a*x?

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Maz

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Re: VCE Methods Question Thread!
« Reply #12823 on: December 10, 2015, 02:43:00 am »
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hey,
I'm going through a chapter about integration but haven't really ever been taught it
besides the basic raise the power by one and divide by the new power...can someone please help me with the
rules of integration?     please :)
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cosine

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Re: VCE Methods Question Thread!
« Reply #12824 on: December 10, 2015, 08:58:12 am »
+5
hey,
I'm going through a chapter about integration but haven't really ever been taught it
besides the basic raise the power by one and divide by the new power...can someone please help me with the
rules of integration?     please :)

To make it easier for yourself, you should remember that integration is the opposite of deriving a function;

1.

This says that the anti-derivative of sin(x) is -cos(x). This is just the universal rule for it, and you can prove it by differentiating -cos(x), so the derivative of -cos(x) = -(-sin(x)) = sin(x).

2.

The anti-diff of cos(x) is sin(x). You can prove it by deriving sin(x), which yields cos(x), so if you 'undo' (anti diff) cos(x) you should get back to the starting function, which was sin(x).

3. , n=/= -1

This is just a rule that you need to memorise. Whenever you have a linear function INSIDE the brackets, like x+3 or 4-4x, and the power of the whole brackets is any number besides -1, you can use the above rule to integrate it.

Example:

Now, a = 3, b = -1, n = -4, plug these into the rule to get:





4.    OR   

This one is like number 3, where the LINEAR expression inside the brackets is raised to the power of -1 when it is reciprocated. So when you have a non-fraction linear expression raised to the power of -1, you must use the above rule to integrate it.

Example:



5.

This one is probably the most simple one, whenever you have e raised to the power of a number, just divide the euler expression by the number and add c to obtain the integral. You can once again prove that this is correct by differentiating the anti-diff:

Example:



So clearly the derivative of equals e^{ax}, so this means that the anti-diff rule above holds.

I would recommend you to just keep practicing anti-differentiating some expressions, until you can fully memorise and utilise the rules above. Just to make things easier for you, try to put a poster of the rules on your wall for a week or two, this is what I did and it immensely helped me. Also for some additional help, just keep in mind when you anti-diff an expression, if you differentiate the result, it should lead back to the anti-diff original expression. Hope this helped xD
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