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October 17, 2025, 09:13:03 pm

Author Topic: VCE Methods Question Thread!  (Read 5742237 times)  Share 

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snowisawesome

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Re: VCE Methods Question Thread!
« Reply #15870 on: January 13, 2018, 12:39:10 pm »
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Yep to both questions
but if (2^x)^2 is the same as (2^2)^x
then (2^x)^2 would = (4^(x^2))
but (2^2)^x = (4)^x
Is there something i'm missing?

VanillaRice

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Re: VCE Methods Question Thread!
« Reply #15871 on: January 13, 2018, 12:49:32 pm »
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but if (2^x)^2 is the same as (2^2)^x
then (2^x)^2 would = (4^(x^2))
but (2^2)^x = (4)^x
Is there something i'm missing?
Remember BIDMAS. The brackets on (4^(x^2)) imply the x is squared.
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snowisawesome

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Re: VCE Methods Question Thread!
« Reply #15872 on: January 13, 2018, 12:53:07 pm »
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Enclosed in spoiler because a reply was posted 36 seconds prior.

(Or a smaller subset of that interval.) The idea is that if \( x\notin (2,\infty) \), then \( g(x) \) is not defined. In a similar way, if \( f(x)\notin (2,\infty)\), then \(g\left[f^{-1}(x)\right] \) is not defined. The easiest way to make sure \(f^{-1}(x)\in (2,\infty) \) is true is to simply make the range of \(f^{-1}\) exactly that.


Regarding the edit:

Where did you get the f^(-1)(x) from?


What's the best way to utilise a group tutor in terms of asking questions (as it's harder to ask individual questions as it's not a private tutor)?

MOD EDIT: Merged double post//Sine
« Last Edit: January 13, 2018, 01:39:58 pm by Sine »

Lear

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Re: VCE Methods Question Thread!
« Reply #15873 on: January 13, 2018, 02:38:58 pm »
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If someone could help me understand B I would be very grateful.
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zhen

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Re: VCE Methods Question Thread!
« Reply #15874 on: January 13, 2018, 02:53:56 pm »
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If someone could help me understand B I would be very grateful.
(Image attached)
Solution manual didn't make sense to me :/

Lear

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Re: VCE Methods Question Thread!
« Reply #15875 on: January 13, 2018, 02:59:27 pm »
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Damn I didn't see that.
Thank you so much Zhen
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Jigsaw

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Re: VCE Methods Question Thread!
« Reply #15876 on: January 16, 2018, 04:16:16 pm »
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Hey,

was wondering if anyone could show me how to do the following question:

state the dilation which maps the graph of f(x) to f1(x):

f(x)= 1/x^2, f1(x) = 5/x^2

I have the worked solution, but the problem is that its filled with too much jargon that is proving difficult to understand.  Thanks :)
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Yertle the Turtle

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Re: VCE Methods Question Thread!
« Reply #15877 on: January 16, 2018, 04:21:14 pm »
+1
Hey,

was wondering if anyone could show me how to do the following question:

state the dilation which maps the graph of f(x) to f1(x):

f(x)= 1/x^2, f1(x) = 5/x^2

I have the worked solution, but the problem is that its filled with too much jargon that is proving difficult to understand.  Thanks :)
For any given x value, what is the change in y values between f(x) and f1(x)?
For x=1, f(1)=1 and f1(x)=5
For x=2, f(2)=1/4 and f1(x)=5/4
For x=3, f(3)=1/9 and f1(x)=5/9

Therefore the dilation factor is 5
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Jigsaw

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Re: VCE Methods Question Thread!
« Reply #15878 on: January 16, 2018, 04:26:18 pm »
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For any given x value, what is the change in y values between f(x) and f1(x)?
For x=1, f(1)=1 and f1(x)=5
For x=2, f(2)=1/4 and f1(x)=5/4
For x=3, f(3)=1/9 and f1(x)=5/9

Therefore the dilation factor is 5

How would I then know if this is a factor of 5 from the x or y axis? Cheers

Edit: Its from the x axis because the y values are changing?
« Last Edit: January 16, 2018, 04:28:02 pm by Jigsaw »
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Re: VCE Methods Question Thread!
« Reply #15879 on: January 16, 2018, 04:28:37 pm »
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How would I then know if this is a factor of 5 from the x or y axis? Cheers
If it is a dilation of 5 from the x axis, then you change y to y/5 then rearrange for y, if it's a dilation from the y axis, you change x to x/5. Correct me if I'm wrong

Yertle the Turtle

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Re: VCE Methods Question Thread!
« Reply #15880 on: January 16, 2018, 04:46:11 pm »
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I just checked it up, and a dilation from the x-axis is when (x,y) maps to (x,b*y) and a dilation from the y-axis is where (x,y) maps to (a*x,y). Hope this helps!
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Lear

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Re: VCE Methods Question Thread!
« Reply #15881 on: January 16, 2018, 05:27:20 pm »
+1
Honestly the above two ways confuse me. The way I simply remember it is a dilation from x axis means you multiply the entire function by a number.

E.g f(x)=1/x
Dilation from x axis by factor of 5
—> 5f(x) = 5/x

Since we are multiplying whatever comes out of f(x) by five, it means we are changing the y value as f(x) gives a y value.

This might be unorthodox and probably won’t make sense to many others but it helps me so it might help you :)
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Jigsaw

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Re: VCE Methods Question Thread!
« Reply #15882 on: January 16, 2018, 05:38:40 pm »
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This made more sense to me! So basically, the first step is to check if the whole function has been multiplied by something, or if only x has? This will tell us if a y value or x value is changing, and thus, if it is a or 1/a?
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Lear

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Re: VCE Methods Question Thread!
« Reply #15883 on: January 16, 2018, 06:38:04 pm »
+1

This made more sense to me! So basically, the first step is to check if the whole function has been multiplied by something, or if only x has? This will tell us if a y value or x value is changing, and thus, if it is a or 1/a?

Yup, it works for me :)
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jazzycab

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Re: VCE Methods Question Thread!
« Reply #15884 on: January 16, 2018, 08:27:40 pm »
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Honestly the above two ways confuse me. The way I simply remember it is a dilation from x axis means you multiply the entire function by a number.

E.g f(x)=1/x
Dilation from x axis by factor of 5
—> 5f(x) = 5/x

Since we are multiplying whatever comes out of f(x) by five, it means we are changing the y value as f(x) gives a y value.

This might be unorthodox and probably won’t make sense to many others but it helps me so it might help you :)
You need to be careful applying this for power functions, as dilations can be described correctly in either direction. For example the transformation for:

can be described as a:

This is because:

This might not seem important, as you can describe transformations however you like (provided they're correct), but consider a multiple choice question where only one option of the two is given, and you only know how to do it one way.