VCE Methods Question Thread!

[integrationbyrecognition]

what should i do before exam 2??

Relax and maybe just go over your bound reference/notes and make sure you have everything you need in there. Good luck for exam 2

[Freddie Hg]

Relax and maybe just go over your bound reference/notes and make sure you have everything you need in there. Good luck for exam 2

Thanks. hope you smash it

[integrationbyrecognition]

Thanks. hope you smash it

Thanks bro, good luck to you as well

[EllingtonFeint]

Hello,
I have a few questions (it’s only 1/2-hope everyone went well on the exams BTW!)
There’s kinda a lot but I don’t want just answers, maybe just an explanation so that I’ll be able to understand how to work I out myself, please?

Thank you

[MB_]

Hello,
I have a few questions (it’s only 1/2-hope everyone went well on the exams BTW!)
There’s kinda a lot but I don’t want just answers, maybe just an explanation so that I’ll be able to understand how to work I out myself, please?

Thank you

I can only see the image of the bottle rocket question and that was answered here

[EllingtonFeint]

Hiii,
Here is an attempted repost of the pictures of those problems I need help with...

[lzxnl]

2. The reference position is 0. You just need to find the smallest distance the particle ever is to 0. Basically, find the turning points (by setting the derivative to zero), and do make sure that the particle never actually reaches x=0, otherwise the smallest distance to 0 is, well, 0.

3. A general point on the line is given by (x,y) = (x, 7-x). You want to find the x value when the distance between (0,0) and this point is the smallest. Use the distance formula to find the squared distance (so as to not involve square roots). Minimising the squared distance is enough; you don't have to minimise the distance itself

4. Do the same thing; you want the distance between (x,-2x-5) and (3,7). Find the squared distance and minimise.

5a. For the vertical distance between two points, note that this means they have the same x value. Therefore, the distance between the two points is just the difference in the y values (you may need to be careful about the sign)

[galaxy21]

Hi,
I am still doing 1/2 methods, but I had a couple of questions that came up while doing a practice exam today, and I would really appreciate if anybody was able to help out.

I had tried to substitute log₃5 into the other equation, and then solve for a and b, but that didn't work. And when I looked at the solutions, I got really confused. It'd be great if somebody would be able to explain how to work this out

[darkz]

Hi,
I am still doing 1/2 methods, but I had a couple of questions that came up while doing a practice exam today, and I would really appreciate if anybody was able to help out.

I had tried to substitute log₃5 into the other equation, and then solve for a and b, but that didn't work. And when I looked at the solutions, I got really confused. It'd be great if somebody would be able to explain how to work this out

This is just an application of log laws

[galaxy21]

This is just an application of log laws

Haha yep looking back at it that makes so much sense. How did I miss that 
Thank you!

[matthewzz]

Hi there! I'm in 1/2 methods and have my exam 1 tomorrow which I have a question for logs, just wondering if anyone can assist?

[f0od]

hey! I am a bit confused about this question regarding finding an exponential model from a table and was wondering if anyone would be able to explain it to me (particular a &c). thank you so much in advance!!

[aspiringantelope]

Hey, may I ask what we need to know about log? Other than the log laws?
and also what does the "a" below the log mean? Or does log.a just mean logarithm?
Thanks


Sorry, I just had a look but I'm supposing a is supposed to be a random number am I right? Or is it the base ? Sorry i'm verrrrrry confused.
EDIT: merged posts. Please refrain from successively posting twice on the same thread by editing your earlier post if you wish to change it. Thanks, Sine.

[S200]

Sorry, I just had a look but I'm supposing a is supposed to be a random number am I right? Or is it the base ? Sorry i'm verrrrrry confused.

Yeah, the \(a\) can be any number.

It's generally said “Log of x in the base a...”

So \(\log_{10} {200}\) would be described as the Log(arithm) of 200 in the base 10...

[aspiringantelope]

Yeah, the \(a\) can be any number.

It's generally said “Log of x in the base a...”

So \(\log_{10} {200}\) would be described as the Log(arithm) of 200 in the base 10...

Wow thanks!
So confusing as a beginner haha >.<