Ok thanks ^^^111^^^^
I've also got another question =[
How do you make
\(3\left(x+2\right)^2\cdot \left(x^2+1\right)-2x\left(x+2\right)^3\) equal \(\left(x+2\right)^2\left(x-3\right)\left(x-1\right)\) ?
I'm having some problems >.<
Hey,
The first step would be to simplify both sides of the equation by dividing them both by (x+2)^2. Then we will have
3(x2+1) - 2x(x+2)3 = (x-3)(x-1). Now by expanding both sides and simplifying we get:
-22x2 -2x4 - 12x -12x3. (Let me know if you want clarification how i ended up with this).
After that we can solve for x by using the factor theorem and long division. So using the factor theorem of polynomials we can say that (x+1) is a factor of the quartic polynomial. Then, by using long division and repeating the process again for the cubic polynomial derived, we can safely say that x = -1 , -2, 0, (I'll let u find the last one
)
Please tell me if I had made any mistakes.
Hope that helps