VCE Methods Question Thread!

[pi]

Do you mean ? If so, then it does have an asymptote at x=3

[oliverk94]

Do you mean ? If so, then it does have an asymptote at x=3

Yer. When I work it out the asymptote is at x=3 but when I graph it CAS calculator it says its x=1.

[pi]

Do you mean ? If so, then it does have an asymptote at x=3

Yer. When I work it out the asymptote is at x=3 but when I graph it CAS calculator it says its x=1.

That shouldn't be happening, what exactly did you type into your CAS (ie. what syntax?)?

[Planck's constant]

That shouldn't be happening, what exactly did you type into your CAS (ie. what syntax?)?

computer says NO

[Planck's constant]

Do you mean ? If so, then it does have an asymptote at x=3

Yer. When I work it out the asymptote is at x=3 but when I graph it CAS calculator it says its x=1.

Trust yourself 
You have either entrered the wrong thing on CAS, or you are misreading the result

[#1procrastinator]

What's the difference between something like [-pi, pi] and [0, 2pi] when you're working with circular functions? Isn't it just the same interval?

I got confused with this when working with complex numbers in specialist but I think it might be more of a trig thing

[rife168]

What's the difference between something like [-pi, pi] and [0, 2pi] when you're working with circular functions? Isn't it just the same interval?

I got confused with this when working with complex numbers in specialist but I think it might be more of a trig thing

If you have then some of the angles within the restriction are negative, such as
whereas for these angles would be given as respectively.
To alternate between the two you just add or subtract

[mfung95]

Could someone please send me the practise sacs and exams for methods 3/4?  >.<" THANK YOUUUUUUU

[dinosaur93]

same here....
preferably practise SACs pls..

[TrueTears]

Could someone please send me the practise sacs and exams for methods 3/4?  >.<" THANK YOUUUUUUU

Practise tests/SACs

[Kaille]

help!
solve the simultaneous equations for x and y. I'd plunk it into the calc but i have to show working...

-(b+c)y - ax = ab
(a+b)x + cy = bc

thanks

[Phy124]

help!
solve the simultaneous equations for x and y. I'd plunk it into the calc but i have to show working...

-(b+c)y - ax = ab
(a+b)x + cy = bc

thanks

(+)








You can probably simplify some things in there but I'm just showing you how to go about it.

Do the same for x i.e. multiply each equation such that you will be able to eliminate y from the equation.

edit: replaced ab(a + b) with ac as the coefficient for y in the second last line and hence answer

[Kaille]

thanks gosh its so complicated!

[Phy124]

No worries Yeah, it can get quite clustered when you have question likes this. Just remember whenever you come up against simultaneous equations just work out how you can eliminate one of the variables, most of the time it will be through relatively easy multiplication/subtraction/addition (e.g. this case) and you should be right from there.

edit: Also please note my edit in the above post for your working out, made a small mistake

[#1procrastinator]

What's the difference between something like [-pi, pi] and [0, 2pi] when you're working with circular functions? Isn't it just the same interval?

I got confused with this when working with complex numbers in specialist but I think it might be more of a trig thing

If you have then some of the angles within the restriction are negative, such as
whereas for these angles would be given as respectively.
To alternate between the two you just add or subtract

Could you please give a couple of different examples? With the unit circle or something...it's just not clicking me with yet :p
Seems a little random at the moment lol

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For what values do the equations  (m-1)x + 5y = 7 and 3x + (m-3)y = 0.7m have infinitely many solutions?

I rearranged it and solved for m (setting the gradients equal) and got m = 6 and m = -2. Why is 6 an answer but -2 isn't (I plotted it and it gave me parallel lines, but why?)