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September 02, 2025, 08:00:07 am

Author Topic: VCE Methods Question Thread!  (Read 5652100 times)  Share 

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Planck's constant

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Re: VCE Methods Question Thread!
« Reply #1665 on: March 06, 2013, 11:50:25 pm »
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Love your work, Ancora_Imparo.
You will be an AN Study Guide author before too long

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Re: VCE Methods Question Thread!
« Reply #1666 on: March 09, 2013, 02:53:58 pm »
0
don't know why im stuck on this one

1 A firm manufacturing jackets finds that it is capable of producing 100 jackets per day, but it
can only sell all of these if the charge to wholesalers is no more than $50 per jacket. On the
other hand, at the current price of $75 per jacket, only 50 can be sold per day.
Assume that the graph of price, $P, against number sold per day N is a straight line.
a Sketch the graph of P against N.
b Find the equation of the straight line.
c Use the equation to find:
i the price at which 88 jackets per day could be sold
ii the number of jackets that should be manufactured to sell at $60 each.

Phy124

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Re: VCE Methods Question Thread!
« Reply #1667 on: March 09, 2013, 04:22:32 pm »
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don't know why im stuck on this one

1 A firm manufacturing jackets finds that it is capable of producing 100 jackets per day, but it
can only sell all of these if the charge to wholesalers is no more than $50 per jacket. On the
other hand, at the current price of $75 per jacket, only 50 can be sold per day.
Assume that the graph of price, $P, against number sold per day N is a straight line.
a Sketch the graph of P against N.
b Find the equation of the straight line.
c Use the equation to find:
i the price at which 88 jackets per day could be sold
ii the number of jackets that should be manufactured to sell at $60 each.
You know that 100 jackets (N1) can be sold per day at a price ($P1) of $50 a jacket and that 50 jackets (N2) can be sold at a price ($P2) of  $75 per jacket, so these are two points on your graph.

- For "a" draw a line which goes through these two points on the set of axis described in the question

- For "b" use the formula for deriving the equation of a straight line (y-y1=m(x-x1), where; m = (y2-y1)/(x2-x1))

- For "ci" sub in 88 for N and solve for $P

- For "cii" Sub in 60 for $P and solve for N
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Markkiieee

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Re: VCE Methods Question Thread!
« Reply #1668 on: March 12, 2013, 12:49:20 am »
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What is the largest possible domain for the function: f(x) = sqroot(9x-x^2)

507

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Re: VCE Methods Question Thread!
« Reply #1669 on: March 12, 2013, 01:20:58 am »
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You cannot square root a negative, so in order for f(x) to be defined:
-x^2+9x>=0
-x(x-9)>=0
So the domain is 0<=x<=9 (graphing -x^2+9x>=0 may help in visualising this.)

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Re: VCE Methods Question Thread!
« Reply #1670 on: March 12, 2013, 08:21:54 am »
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You cannot square root a negative, so in order for f(x) to be defined:
-x^2+9x>=0
-x(x-9)>=0
So the domain is 0<=x<=9 (graphing -x^2+9x>=0 may help in visualising this.)

thans, what does the 9x do to the grap?

Daenerys Targaryen

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Re: VCE Methods Question Thread!
« Reply #1671 on: March 12, 2013, 04:42:02 pm »
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makes another x intercept
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abcdqdxD

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Re: VCE Methods Question Thread!
« Reply #1672 on: March 12, 2013, 06:39:28 pm »
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State the transformations to get from y=10e^x to y=10e^(2x-1)+1

Is it dilation by factor of 1/2 parallel x, translate 1 unit in positive y direction, 1/2 units in positive x direction?

Daenerys Targaryen

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Re: VCE Methods Question Thread!
« Reply #1673 on: March 12, 2013, 06:53:27 pm »
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State the transformations to get from y=10e^x to y=10e^(2x-1)+1

Is it dilation by factor of 1/2 parallel x, translate 1 unit in positive y direction, 1/2 units in positive x direction?
yes
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Markkiieee

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Re: VCE Methods Question Thread!
« Reply #1674 on: March 13, 2013, 06:18:01 pm »
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What are the formulas for dilation?
« Last Edit: March 13, 2013, 06:54:32 pm by Markkiieee »

Ancora_Imparo

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Re: VCE Methods Question Thread!
« Reply #1675 on: March 13, 2013, 08:39:10 pm »
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VCE TUTOR FOR BIOLOGY, CHEMISTRY, MATHEMATICAL METHODS (CAS), PHYSICS & SPECIALIST MATHEMATICS. TUTORING AT GLEN WAVERLEY LIBRARY OR MONASH UNIVERSITY, CLAYTON. PM ME IF INTERESTED.

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Re: VCE Methods Question Thread!
« Reply #1676 on: March 16, 2013, 03:14:31 pm »
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A chemical manufacturer has an order for 500 litres of a 25% acid solution (i.e. 25% by
volume is acid). Solutions of 30% and 18% are available in stock.
a How much acid is required to produce 500 litres of 25% acid solution?

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Re: VCE Methods Question Thread!
« Reply #1677 on: March 16, 2013, 03:22:21 pm »
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When will the gradient function be undefined? The answers say when x = 1/3, but I don't quite get why it will be undefined at that point.
Also, what does 'sign' mean in reference to the CAS syntax you get if you type that on a CAS?
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Daenerys Targaryen

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Re: VCE Methods Question Thread!
« Reply #1678 on: March 16, 2013, 03:24:44 pm »
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at x=1/3 is the cusp of the absolute value graph. at the cusp of any graph the gradient is undefined
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Conic

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Re: VCE Methods Question Thread!
« Reply #1679 on: March 16, 2013, 03:27:41 pm »
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When will the gradient function be undefined? The answers say when x = 1/3, but I don't quite get why it will be undefined at that point.
Also, what does 'sign' mean in reference to the CAS syntax you get if you type that on a CAS?
"Sign" refers to the sign or signum function, which is related to derivatives of modulus functions.
http://en.wikipedia.org/wiki/Signum_function
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