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August 23, 2025, 06:38:56 pm

Author Topic: Wenhao's Biology 3/4 Ques Thread!!!  (Read 20232 times)  Share 

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LOLs99

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #45 on: February 05, 2012, 02:52:07 pm »
0
I will learn both of them then.I haven't study before the concentration-isotonic,hypotonic,hypertonic...can someone just explain it?
Do you get like some info before the sacs?
So basically light dependent requires light energy while light independent requires?high energy compound as in(for light independent)?

Thanks for taking the time to help me out, wish you guys the best in vce and uni. I will try my best...what's the marks I should get for my sac 1 which will be out of 25 marks in order to get 40+ or 45+ raw?

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paulsterio

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #46 on: February 05, 2012, 02:54:00 pm »
+1
Isotonic = same concentration (for example, IV drips are isotonic to blood)
Hypotonic = lower concentration (for example A is hypotonic to B means that conc(A)<conc(B))
Hypertonic = higher concentration

LOLs99

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #47 on: February 05, 2012, 03:38:02 pm »
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I get it. But I don't know if you can say this for concentration- concentration is the solute containing in the solvent,means that IV drips have the same solute concentration or same solvent concentration to blood?

I have to clarify the question stated above.
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paulsterio

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #48 on: February 05, 2012, 04:31:36 pm »
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you can't have solute concentration or solvent concentration, concentration has many units, but the general definition of concentration is:



If you are referring to concentration in mol/L, for example.

LOLs99

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #49 on: February 06, 2012, 10:29:01 pm »
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So low solute concentration means it has insoluble solute in a concentration?
I just half half of what you said but that's fine. I will get it later...
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Reckoner

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #50 on: February 06, 2012, 10:43:52 pm »
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http://www.youtube.com/watch?v=_slUL3kMZlU This video explains the hypo/hyper/iso tonic solutions well, and in relation to osmosis as well.

And low solute concentration doesn't mean that there are insoluble particles in it. For example, pure water would have very low solute concentration, but would also have no insoluble compounds.

LOLs99

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #51 on: February 06, 2012, 10:58:12 pm »
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thanks for the link. 'For example, pure water would have very low solute concentration, but would also have no insoluble compounds.'- can you make more explanations so I can fully understand it.
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Reckoner

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #52 on: February 06, 2012, 11:08:29 pm »
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When referring to solute concentration with osmosis, ignore the insoluble particles, they are irrelevant.The example was just showing that solute and insoluble compounds are not linked in terms solute concentration.

I'm sure that as you progress further in the unit, these solute concentration things will click. Just give them some time to settle in your head for a week or so if you are having trouble.   

paulsterio

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Re: My Questions regarding to VCE Bio Unit 3~2012
« Reply #53 on: February 06, 2012, 11:12:22 pm »
+1
Another way of thinking about it is this.

You have a glass with 250mL of water in it. You add 50 grams of salt (NaCl)



You now decide to add 5 rocks (rocks are insoluble) to the glass, the rocks sink to the bottom. Does it affect the amount of salt? No. Does it affect the amount of salt? No. Does it affect the concentration? No.

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Re: Wenhao's Biology 3/4 Ques Thread!!!
« Reply #54 on: February 29, 2012, 08:40:57 pm »
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How did you do on the first Sac, bro?

LOLs99

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Re: Wenhao's Biology 3/4 Ques Thread!!!
« Reply #55 on: March 15, 2012, 12:58:30 pm »
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Hey guys, I need some help with enzymes sac 2....

HOw much in depth do I require to understand?
and do I need to memorize a few enzymes just in case...
and for the factors affecting the rate, do I need to know very well for all the factors or just pick a few?

Thanks ppl!
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Re: Wenhao's Biology 3/4 Ques Thread!!!
« Reply #56 on: March 15, 2012, 04:45:09 pm »
+1
We didn't need too much detail. Know the different models of enzymes and substrates. Also know that an inactive enzyme is not denatured, rather it is below its optimum temperature. Choose a few factors. Our stated what would affect the activity of an enzyme, so enzyme concentration is not recommended.
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Jezza

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Re: Wenhao's Biology 3/4 Ques Thread!!!
« Reply #57 on: March 15, 2012, 05:24:53 pm »
+1
Hey guys, I need some help with enzymes sac 2....

HOw much in depth do I require to understand?
and do I need to memorize a few enzymes just in case...
and for the factors affecting the rate, do I need to know very well for all the factors or just pick a few?

Thanks ppl!
Hey mate, you must know the Lock and Key model and The Induced Fit Model and be able to describe and possibly draw the diagrams, and about the factors that affect Enzyme activity such as pH and Temperature. 

Also know about enzymes and there functions obviously. Many of the questions on my sac were related to the Prac, so make sure you understand your Prac throughly.
« Last Edit: March 15, 2012, 08:02:32 pm by Jezza »

pi

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Re: Wenhao's Biology 3/4 Ques Thread!!!
« Reply #58 on: March 15, 2012, 06:13:39 pm »
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and for the factors affecting the rate, do I need to know very well for all the factors or just pick a few?


Learn about 4 or 5, here are some I can think of from the top of my head: concentration (of enzyme and substrate), temperature, radiation, pH, inhibitors (and concentration), co-enzymes (and concentration), etc.

Shenz0r

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Re: Wenhao's Biology 3/4 Ques Thread!!!
« Reply #59 on: March 15, 2012, 06:34:26 pm »
+2
Just describing how each factor actually affects enzyme activity:

*Heat - By adding heat, you overcome/break the weak intermolecular bonds (such as hydrophobic interactions and hydrogen bonding) that hold the shape of the secondary and tertiary structures in the enzyme, and hence the enzyme will denature and enzyme activity will sharply drop after the critical point (the temperature where enzymes begin to denature)
*pH - In order to maintain a constant level of pH, amino acids in the enzyme will donate or accept hydrogen ions, so that the pH level is stabilised. However, this changes the intermolecular bonds that form between the secondary and tertiary structures (as you've pretty much changed the chemical structure of the amino acid), and hence the protein will denature. The curve for pH affecting enzyme activity resembles a bell-curve because the pH scale is a logarithmic scale, which means that it goes up in factors of 10 (pH 6 is 10 times more acidic, and has 10x more hydrogen ions than pH 7), and so the drop in enzyme activity is not as dramatic as temperature.
*Co-enzymes - these basically help the enzyme to accommodate the substrate better, and make it easier to fit. Hence, enzyme activity will increase as more substrates will easily bind to the active site of the enzyme.
*Inhibitors - These are divided into two categories, non-competitive and competitive, which bind completely to an enzyme's active site, preventing the substrate from binding to the enzyme. If you have a high concentration of competitive inhibitors, enzyme activity will decrease as less substrate is able to bind to the active sites of enzymes. However, if the concentration of substrate is greater than the concentration of competitive inhibitors, enzyme activity will decrease less as the substrate becomes more 'competitive', and there is a lesser likelihood of an inhibitor binding to an active site. Non-competitive inhibitors almost permanently bind to enzymes, halting reactions between substrates and enzymes completely.
-Concentration of enzyme - Obviously, as you increase the concentrations of enzyme, there will be a great increase in the rate of reaction - more enzymes are bumping and binding into substrates.
-Concentration of substrate - Initially, increasing the substrate concentration will increase the rate of reaction as there is a greater chance of substrates binding to active sites, but it slowly decreases as the enzyme concentration becomes 'saturated', which is when the enzymes are reacting at full capacity and cannot increase the rate of reaction.
« Last Edit: March 15, 2012, 06:36:08 pm by Shenz0r »
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