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May 13, 2025, 05:30:19 pm

Author Topic: Ahh.liz's Specialist Mathematics Queries  (Read 4771 times)  Share 

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rife168

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #15 on: March 04, 2012, 08:01:28 pm »
+1
A quicker way to do this would be to simply factorise and solve for z.
Doing so, I found that
From this, you can see that a has to be as
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paulsterio

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #16 on: March 04, 2012, 08:11:36 pm »
+2
what's with the tildes under the i, it's not a vector? :P

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #17 on: March 04, 2012, 08:27:15 pm »
+1
what's with the tildes under the i, it's not a vector? :P
Force of habbit (a couple of months after yr 12 and I'm already rusty :P), I'll fix it up now. Thanks Paul, also note guys doing that on the exam will lose you marks, so take note of that.
« Last Edit: March 04, 2012, 08:30:15 pm by b^3 »
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ahh.liz

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #18 on: March 08, 2012, 06:57:37 pm »
0
How about this one?

Solve for x in sqrt(2)sin^2(x) = cos(x), x is an element of [0, 2pi]
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nubs

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #19 on: March 08, 2012, 07:44:10 pm »
+1
sqrt(2)(1-cos^2(x))=(cos(x))
sqrt(2) - sqrt(2)(cos^2(x)) - cos(x) = 0
Let cos(x) = a

-sqrt(2)a^2 - a + sqrt(2)  = 0

go on from there :)
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ahh.liz

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #20 on: March 08, 2012, 09:09:53 pm »
0
Ooh very nice :) Thank you.
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ahh.liz

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #21 on: April 06, 2012, 12:10:00 pm »
0
Thanks for that.

Hey, so we're been learning about vectors recently and we hit dot product, although I understand the mathematical arithmetic, I'm not sure what it is that I'm working out. All I see is a number and I'm not sure what it's trying to tell me :P. Haha. Would anyone be able to shed some light on my little dilemma? :)
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rife168

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #22 on: April 06, 2012, 04:30:45 pm »
+1
I found a useful link here, although you can probably disregard the stuff about Gauss's Law.

It may seem quite circular a definition, but when you think about projections of one vector on another, i.e. and   then it gives more clarity to what the dot product means. Remember to consider the fact that the dot product on it's own doesn't give you all that much information, but when you start introducing unit vectors and magnitudes it can be very useful for projections, areas and of course finding the angle between two vectors.


edit: The wikipedia page has some helpful and interesting diagrams and whatnot on it.
« Last Edit: April 06, 2012, 04:32:33 pm by fletch-j »
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Bhootnike

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #23 on: April 06, 2012, 10:31:55 pm »
+1
Dot product (or scalar product, since it is found by multiplying 2 magnitudes and ) , as you know is given by:



its called dot product cause we use a dot to show the multiplication btw!

In essence, I think what you work out, most of the time is the angle between two vectors.
This comes into play when considering if vectors are parallel or perpendicular to each other, and thus this can help in proving something like a quadrilateral, square, rhombus, trapezium...

also in a physical aspect, it can be used in cases such as:

REFER TO ATTACHMENT HERE

im gonna show some applied physics here so skip on if you wish!

the stickfigure is pulling the object with a constant force (vector quantity) so that  it moves along the horizontal ground right.
Consider the following:
work done = our dot product in this example
the work done in physics, is work done = force x displacement - 2 vector quantities
the component of the force being applied, as in the right diagram, in the direction of motion =

so the work done, through a distance of  is thus given by the distance moved(i.e ), , multiplied by the magnitude of the component of the force, in the direction of motion, i.e.

this then gives us our: , where   is the angle between a and b when they are placed TAIL TO TAIL !

in a physics sense, to use the least possible force, we would need to pull horizontally, so that we are pulling in the same direction as we want the object to move. Then we would have θ = 0 and cos θ= 1 so that the work done , which = magnitude of the force multiplied by the distance moved in the direction of the force.



So...! don't dwell too much cause i dont think we need to go that far, however keep in mind the usefulness of the dotproduct and the applications of it, since who knows.. a question , maybe similarly described above might happen to appear on the exam. AND I HOPE IT DOES SO I GET 10/10. :D haha nah. yer hope that helped...
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ahh.liz

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #24 on: May 16, 2012, 04:20:49 pm »
0
Thanks for the help (above) and I have another query...I'm not quite sure how to anti differentiate:

sec^2(x)cos^n(x) where n is an element of Z+

Any suggestions? :P
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pi

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #25 on: May 16, 2012, 04:41:17 pm »
+1
Just a couple of questions:

1.
This is from MathsQuest (:o), p. 264
Evaluate:
I got upto , which is only one step from the question, and am now stuck :(

For question 1, its actually a typo. I spent half an hour trying to figure it out as well and realised it was a typo after reading the worked solutions. Cos is meant to be Tan. Then its simple enough to anti diff.
This is why I hate mathquest. Hope this helped.

:)

Mao

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #26 on: May 17, 2012, 11:11:14 pm »
+4
According to Mathematica:



where and , is the Euler-Gamma function, which returns for integer, and for some odd n.
« Last Edit: May 17, 2012, 11:16:52 pm by Mao »
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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #27 on: May 17, 2012, 11:22:40 pm »
+3
Mao's being epic as usual
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ahh.liz

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #28 on: May 21, 2012, 08:15:29 pm »
0
Oh hahaha! Thanks guys! Really appreciate it.

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Re: Ahh.liz's Specialist Mathematics Queries
« Reply #29 on: May 24, 2012, 12:21:21 pm »
0
http://www.wolframalpha.com works a gem for solving equations.
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