1)
okay I've come across this question in a random practice exam:
NH4Cl(s) <--> NH3(g) + HCl(g), dH = +176 kJ mol-1
when solid NH4Cl is added to the equilibrium, what will happen to the forward and reverse rates?
now I know LCP might say that if you add stuff to the LHS, the equilibrium position will be shifted to the right, hence the rate of forward reaction will increase instantaneously and then decrease a little and the reverse reaction increase, before equilibrium is regained. but does adding solid NH4Cl really affect the equilibrium at all? if we consider the Kc of the reaction, NH4Cl is a solid, so the concentration of NH4Cl really isn't relevant. so Kc = [NH3][HCl]. now if we add NH4Cl, Qc still remains the same as Kc. in other words, it appears that adding NH4Cl doesn't really affect the equilibrium in any way, since the concentration of the solid more or less remains constant, if it is even right to speak of concentration of solid.
what are your thoughts? I may be missing something critical...in which case I apologise in advance for the stupid question :p
2) also just a quickie: if the question does not explicitly tell us to use LCP, can we argue using formulas such as the van't hoff equation? I don't understand how one can really use LCP to explain why, for an endothermic reaction, an increase in temp results in an increase in Kc. sure, the equilibrium position will shift to the right, but that doesn't mean Kc increases.
thanks!