Can someone explain to me why adding an inert gas does not affect equilibrium? I can see that doing so would increase the overall pressure, at the same time it would also decrease the number of collisions between the reactants because the reactants would now be colliding with the gas instead of each other. The answer that the teacher gave me was that the overall pressure is affected but not the partial pressure. Another teacher said that even though collisions increase, successful collisions do not increase, which I think is what I said earlier. So what's the actual explanation for this? Any help is appreciated 
It all depends on how the inert/noble gas is added:
If it is added at a
constant volume, the total pressure present in the system will obviously increase. But the concentration of the products and reactants will not change, hence, the equilibrium will not be affected.
If the inert gas is added at a
constant pressure, the total volume will increase, therefore, as the number of moles per unit of volume will decrease, as now the moles are more spread out in the system.
Take the following equation for example:
2 NH
3 (g) ⇌ N
2 (g) + 3H
2 (g)According to Le Chatelier's Principle, as there is now a lower concentration, the system will shift in the direction of more moles (so that the system can offset the lower in concentration), this means that the equilibrium will shift to the right.