Further Maths Exam 2: Answers + Discussion!

[Mayesy]

Is it still possible for me to get a mark for the Hungarian algorithm in networks if I said 'only three vertical or horizontal lines are required to cover all zeroes, and for it to be complete 4 lines are required?

[DanielJ]

Area was on the x axis, I'm looking at the exam now, only two points were to the right of x=6.6

Well damn, means the left column being Y axis and right column being X axis actually got me. Do you see what I mean with the right side of the graph? It looks like it would begin to flatten out

[jt33]

Can you explain how you got this?
I think you're right

just the cost against revenue
3.5n=42.8+2(n-10)

so n=15.2kg and isnt rounded as equation is continuous

[Lucho23]

just the cost against revenue
3.5n=42.8+2(n-10)

so n=15.2kg and isnt rounded as equation is continuous

Yeah you're correct. I assumed that everything was only based on purchasing 100kg. Modifying the answers now.

[redcracker]

how was
 7257 votes.
obtained for q3b matrices

i believe it should be 6451
i got this from doing T^4 (as S1 is january) times S1 to give may
then used T1 times this matrix
then extracted 6451

someone please confirm??

[Dan1995]

how was
 7257 votes.
obtained for q3b matrices

i believe it should be 6451
i got this from doing T^4 (as S1 is january) times S1 to give may
then used T1 times this matrix
then extracted 6451

someone please confirm??

The question required the number of votes in June, which would be s6, not s5.So it needed to be T⁵

[Dan1995]

Is it still possible for me to get a mark for the Hungarian algorithm in networks if I said 'only three vertical or horizontal lines are required to cover all zeroes, and for it to be complete 4 lines are required?

That's hard to tell, as the question said "at this stage of the hungarian algorithm" it was only up to the column reduction, the next step would have been to draw lines to cover the zeros, as they were not drawn it is not clear which way the marks will be awarded.

[Dan1995]

Well damn, means the left column being Y axis and right column being X axis actually got me. Do you see what I mean with the right side of the graph? It looks like it would begin to flatten out

I see what you mean, however as there are no more data points that clearly show the curve flattening out, I would still suggest that it is just a very weak linear model.

[paulthegreen]

The question required the number of votes in June, which would be s6, not s5.So it needed to be T⁵

I also got 6451, the new matrix times S5 gives the new value for S6.

[Dantini]

Networks

b. Tasks can only be assigned where a zero exists, Brianna has no zeros in her respective column, therefore she cannot be assigned a task and the optimal task allocation can not be made.


Matrices
c. The total female population of the city.

3a. 50%
b. 7257 votes.

Hey mate would I have been alright explaining the insufficient lines for  the task allocation question rather than stating no zeros in that column?

Shouldn't it be the total ADULT female population of the city? I Feel like you'd have lost a mark for saying total female when it only specified adult females.

Can you explain how you came to your answer for 3a of the last Matrices question please? Thanks

[redcracker]

The question required the number of votes in June, which would be s6, not s5.So it needed to be T⁵

S1 is jan, so multiply with T^4 so get to may, as specified in the question
then multiply this with the new matrix T1 that they give you
this takes you to S6, which is june

[jt33]

for the graphs and relations question where you had to show the points where the min fertiliser is used, i drew a line over the line from (1000,3000) to (3000,1000) will that get the 2 marks?

[vididid]

how was
 7257 votes.
obtained for q3b matrices

i believe it should be 6451
i got this from doing T^4 (as S1 is january) times S1 to give may
then used T1 times this matrix
then extracted 6451

someone please confirm??


omg yes, wondering the same!!

[clidedescope]

For the matrices question regarding why the two are defined (sorry, on mobile and can't see which question it is), do you think I could get a mark for saying that: "they are defined because the number of columns in matrix (insert name here) is equal to the number of rows in matrix (insert name here)" without specifically saying they were 2?

[redcracker]

I see what you mean, however as there are no more data points that clearly show the curve flattening out, I would still suggest that it is just a very weak linear model.

to add to this, the r value only applies if the relationship is linear (this is not proof but it does support the fact that it was linear)