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September 11, 2025, 08:05:47 am

Author Topic: HSC Chemistry Question Thread  (Read 1276966 times)  Share 

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massive

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Re: Chemistry Question Thread
« Reply #1305 on: November 02, 2016, 03:12:17 pm »
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Can someone please do this :( the answer is 12.56

jakesilove

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Re: Chemistry Question Thread
« Reply #1306 on: November 02, 2016, 03:14:27 pm »
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Anyone have an idea?

Hey! Figure out the moles of Lead chloride using the final mass. The moles of Lead chloride will equal the moles of Lead, so we can just plug this value for 'n' into C=n/v (using a volume of 50mL, the initial volume) to get a concentration out!
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kimmie

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Re: Chemistry Question Thread
« Reply #1307 on: November 02, 2016, 03:15:09 pm »
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How do we measure biological oxygen demand?

massive

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Re: Chemistry Question Thread
« Reply #1308 on: November 02, 2016, 03:16:38 pm »
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Hope this makes sense :D
(Image removed from quote.)
http://imgur.com/Fc4ehZQ
Damn thanks so much! can you have a look at the other q i posted as well please  :D

noonedoesnt

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Re: Chemistry Question Thread
« Reply #1309 on: November 02, 2016, 03:18:14 pm »
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Hey! Figure out the moles of Lead chloride using the final mass. The moles of Lead chloride will equal the moles of Lead, so we can just plug this value for 'n' into C=n/v (using a volume of 50mL, the initial volume) to get a concentration out!

the only part i don't understand is why we use the 50 not the 25mL

jakesilove

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Re: Chemistry Question Thread
« Reply #1310 on: November 02, 2016, 03:22:28 pm »
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Can someone please do this :( the answer is 12.56

We know that the molar ratio is 1:2 (one mole of Base requires two moles of Acid).







If we use 0.01 moles of acid, that will take up 0.005 moles of base, leaving us with 0.00355 moles of base left. The concentration of Hydroxide is therefore



Now, pH is 14+pOH, so 1-log(0.0182)=12.26. I think I probably messed up some calculation error somewhere, but that's the general method, so you can go back over and check each step so you can understand how to answer a question like this!
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jakesilove

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Re: Chemistry Question Thread
« Reply #1311 on: November 02, 2016, 03:23:51 pm »
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the only part i don't understand is why we use the 50 not the 25mL

Because the lead collected was as a result of 50mL of the pond sample, and we're interested in the lead concentration in the pond :)
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jakesilove

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Re: Chemistry Question Thread
« Reply #1312 on: November 02, 2016, 03:26:00 pm »
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How do we measure biological oxygen demand?



Above is a super condensed version of what you need to know. You probably don't have time to go over the section in depth, and understand it properly, so just throw in some of the buzzwords I've outlined and you can still get all the marks :)
ATAR: 99.80

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WLalex

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Re: Chemistry Question Thread
« Reply #1313 on: November 02, 2016, 03:28:00 pm »
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Nup, turns out that acetic acid is stronger than citric acid. That's just a fact, memorise it!

buuuut...does not acetic acid only ionise around 1% whereas citric is around 8% (would that not mean citric is a stronger acid)??
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jakesilove

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Re: Chemistry Question Thread
« Reply #1314 on: November 02, 2016, 03:32:29 pm »
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buuuut...does not acetic acid only ionise around 1% whereas citric is around 8% (would that not mean citric is a stronger acid)??

Yep, you're definitely right about that actually. Sorry, I don't remember what the original question was or why I wrote what I did; presumably, the thing to get out of this is that in terms of ionisation, HCl ionises the most, then citric, then acetic acid.
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massive

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Re: Chemistry Question Thread
« Reply #1315 on: November 02, 2016, 03:48:48 pm »
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We know that the molar ratio is 1:2 (one mole of Base requires two moles of Acid).







If we use 0.01 moles of acid, that will take up 0.005 moles of base, leaving us with 0.00355 moles of base left. The concentration of Hydroxide is therefore



Now, pH is 14+pOH, so 1-log(0.0182)=12.26. I think I probably messed up some calculation error somewhere, but that's the general method, so you can go back over and check each step so you can understand how to answer a question like this!

Thanks for this, does the fact that calcium hydroxide releases 2 OH make a difference?? :S

jakesilove

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Re: Chemistry Question Thread
« Reply #1316 on: November 02, 2016, 03:50:13 pm »
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Thanks for this, does the fact that calcium hydroxide releases 2 OH make a difference?? :S

Yeah, see my initial line (knowing that it is a 1:2 reactions allows me to find the limiting reagent)
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kimmie

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Re: Chemistry Question Thread
« Reply #1317 on: November 02, 2016, 04:33:54 pm »
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How does electroplating work?

jakesilove

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Re: Chemistry Question Thread
« Reply #1318 on: November 02, 2016, 04:49:25 pm »
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How does electroplating work?

Hey!

Electroplating works by setting up an electrolytic cell, with an anode and a cathode. Say we wanted to coat Iron is Silver. We would make Iron the Cathode, and Silver at the Anode. We would immerse both in a solution of Silver nitrate. The anode oxidises, thus producing more Silver ions. The cathode reduces, converting silver ions into silver metal, which plates the cathode. So, just set up the cathode with whatever you want to coat, set up the anode and the electrolyte with whatever you want the cathode to be coated in, and pump through some current!
ATAR: 99.80

Mathematics Extension 2: 93
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ProfLayton2000

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Re: Chemistry Question Thread
« Reply #1319 on: November 02, 2016, 04:59:07 pm »
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How does including and outlier affect the validity, reliability and accuracy of results?
(Specifically HSC 2004 q20)