Login

Welcome, Guest. Please login or register.

October 12, 2025, 02:31:04 pm

Author Topic: HSC Chemistry Question Thread  (Read 1293047 times)  Share 

0 Members and 5 Guests are viewing this topic.

HighTide

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 208
  • Sink or swim
  • Respect: +48
Re: Chemistry Question Thread
« Reply #1785 on: March 05, 2017, 11:43:36 am »
0
I would like some clarification on this as well! Someone told me that Na+ is extremely weak because it's the conjugate acid of NaOH, a strong base, is this right?
Sup,
Not sure if this has been answered before, but thinking about it like this should help:
I'll just take a strong acid HA as the example. So HA + water --> A- and hydronium. For HA to be a strong acid, it must ionize to completion in water. Hence if you set up an acidity constant Ka will be very high.

Now consider, the reverse of the equation, so: A- + hydronium --> HA + water. In this case, if A- was a strong conjugate base, then, it would accept the hydrogen and form HA, and hence its basicity constant would be high. So the problem with this is that you can't have a high Ka for one reaction, and a high Kb for its backwards reaction, because then you're not having complete ionization. Hence it should be: strong acid --> weak conjugate base, strong base--> weak conjugate acid, weak base --> strong conjugate acid, weak acid --> strong conjugate base.

So in the case of NaOH, which is a very strong base, we will have a very weak conjugate acid Na+. It's basically an inverse relationship. The higher the acidity, the lower the basicity. eg. HCl is a strong acid, Cl- is a weak conjugate base.

Hope this helps
2014-2015: VCE
2016-2018: Bachelor of Biomedical Science

ch3ntastic

  • Guest
Re: Chemistry Question Thread
« Reply #1786 on: March 05, 2017, 08:32:12 pm »
0
For the "Standard Potentials" sheet supplied in the exams. Potassium is at the top and fluorine is at the bottom. Which one is the stronger oxidant/reductant? I get really confused between the whole OIL-RIG and its agents. Thanks ;)

armtistic

  • Forum Regular
  • **
  • Posts: 72
  • Respect: 0
Re: Chemistry Question Thread
« Reply #1787 on: March 05, 2017, 09:14:22 pm »
0
Hey Guys.

I've noticed when it comes to the equations for the batteries i.e. dry cell or silver-button cell in POM the equations vary widely between sources.

I was wondering someone could point out which exactly would be most desirable to use in the HSC and also how do you even remember such complex equations?

Also how important are the solubility rules?
ATAR: 99.70

kiwiberry

  • HSC LECTURER
  • Forum Obsessive
  • ***
  • Posts: 315
  • Respect: +97
Re: Chemistry Question Thread
« Reply #1788 on: March 05, 2017, 09:28:08 pm »
0
For the "Standard Potentials" sheet supplied in the exams. Potassium is at the top and fluorine is at the bottom. Which one is the stronger oxidant/reductant? I get really confused between the whole OIL-RIG and its agents. Thanks ;)

As you go up the standard potentials sheet, ease of oxidation increases (as does reactivity), so K(s) is the strongest reductant. This means that K+ is the weakest oxidant. All the species on the right are reducing agents, and all the ones on the left are oxidising agents :)
HSC 2017: English Adv (93) | Maths Ext 1 (99) | Maths Ext 2 (97) | Chemistry (95) | Physics (95)
ATAR: 99.85

jakesilove

  • HSC Lecturer
  • Honorary Moderator
  • Part of the furniture
  • *******
  • Posts: 1941
  • "Synergising your ATAR potential"
  • Respect: +196
Re: Chemistry Question Thread
« Reply #1789 on: March 06, 2017, 09:15:31 am »
0
Hey Guys.

I've noticed when it comes to the equations for the batteries i.e. dry cell or silver-button cell in POM the equations vary widely between sources.

I was wondering someone could point out which exactly would be most desirable to use in the HSC and also how do you even remember such complex equations?

Also how important are the solubility rules?

Hey! It's important to have SOME kind of equation, but as long as it balances, it won't really matter what it is. As you've said, there are plenty of variations on the internet. Pick the easiest one, and learn it off by heart!

Solubility rules are vital. You need to know them, as you could have up to 8 marks in an HSC exam relying on these principles. They're tough to remember, but with enough practice, you'll do it!
ATAR: 99.80

Mathematics Extension 2: 93
Physics: 93
Chemistry: 93
Modern History: 94
English Advanced: 95
Mathematics: 96
Mathematics Extension 1: 98

Studying a combined Advanced Science/Law degree at UNSW

J.B

  • Trendsetter
  • **
  • Posts: 123
  • Respect: 0
Re: Chemistry Question Thread
« Reply #1790 on: March 06, 2017, 02:55:43 pm »
0
Hi,
I was just wondering why is sodium ethanoate written as CH3COONa, if the Na is the cation and the ethanoate the anion? As I would have automaticallly swapped them around?
Thanks.

jakesilove

  • HSC Lecturer
  • Honorary Moderator
  • Part of the furniture
  • *******
  • Posts: 1941
  • "Synergising your ATAR potential"
  • Respect: +196
Re: Chemistry Question Thread
« Reply #1791 on: March 06, 2017, 03:02:11 pm »
0
Hi,
I was just wondering why is sodium ethanoate written as CH3COONa, if the Na is the cation and the ethanoate the anion? As I would have automaticallly swapped them around?
Thanks.

Hey! It's really only written like that to indicate how the bonding has occurred. The Sodium atom is bonded to one of the Oxygen atoms (the one that isn't double bonded), as suggested by the empirical formula. Make sense?
ATAR: 99.80

Mathematics Extension 2: 93
Physics: 93
Chemistry: 93
Modern History: 94
English Advanced: 95
Mathematics: 96
Mathematics Extension 1: 98

Studying a combined Advanced Science/Law degree at UNSW

J.B

  • Trendsetter
  • **
  • Posts: 123
  • Respect: 0
Re: Chemistry Question Thread
« Reply #1792 on: March 06, 2017, 03:10:27 pm »
0
Hey! It's really only written like that to indicate how the bonding has occurred. The Sodium atom is bonded to one of the Oxygen atoms (the one that isn't double bonded), as suggested by the empirical formula. Make sense?

Ok thankyou, so in an exam is it best to write it like this?

jakesilove

  • HSC Lecturer
  • Honorary Moderator
  • Part of the furniture
  • *******
  • Posts: 1941
  • "Synergising your ATAR potential"
  • Respect: +196
Re: Chemistry Question Thread
« Reply #1793 on: March 06, 2017, 04:51:48 pm »
0
Ok thankyou, so in an exam is it best to write it like this?

I reckon so! It isn't a big deal, but I think that form is just easier to work with :) Also, it makes it easier for you to remember the ionisation (ie. the Na just popping off).
ATAR: 99.80

Mathematics Extension 2: 93
Physics: 93
Chemistry: 93
Modern History: 94
English Advanced: 95
Mathematics: 96
Mathematics Extension 1: 98

Studying a combined Advanced Science/Law degree at UNSW

Kle123

  • Forum Regular
  • **
  • Posts: 60
  • Respect: +1
Re: Chemistry Question Thread
« Reply #1794 on: March 07, 2017, 05:14:36 pm »
0
200mL of a same concentrated sulfuric acid (18M) was dropped by accident.
Possible neutralising substances available: 300mL of 2M NaOH(aq) solution, 200g packet of solid sodium hydrogen carbonate (NaHCO3) or 100 g of NaOH pellets
Question: which substance would be most appropriate clean up neutralising agent and why?

Newbalance101

  • Adventurer
  • *
  • Posts: 8
  • Respect: 0
Re: Chemistry Question Thread
« Reply #1795 on: March 07, 2017, 05:20:03 pm »
0
How do you add half equations together? I'm really bad at it :/

kiwiberry

  • HSC LECTURER
  • Forum Obsessive
  • ***
  • Posts: 315
  • Respect: +97
Re: Chemistry Question Thread
« Reply #1796 on: March 07, 2017, 05:52:04 pm »
+1
200mL of a same concentrated sulfuric acid (18M) was dropped by accident.
Possible neutralising substances available: 300mL of 2M NaOH(aq) solution, 200g packet of solid sodium hydrogen carbonate (NaHCO3) or 100 g of NaOH pellets
Question: which substance would be most appropriate clean up neutralising agent and why?

NaOH isn't a good neutralising agent in general because it's a strong base, so if excess is used by accident, the spill would become dangerous again. This leaves NaHCO3, which is good neutralising agent because it is weak, bubbles during neutralisation so you're able to see when the reaction has finished, and because it's solid, it helps prevent the spill from spreading. Not relevant here, but NaHCO3 is also amphiprotic which is beneficial if the spilt substance is unknown because it can neutralise both acids and bases
HSC 2017: English Adv (93) | Maths Ext 1 (99) | Maths Ext 2 (97) | Chemistry (95) | Physics (95)
ATAR: 99.85

kiwiberry

  • HSC LECTURER
  • Forum Obsessive
  • ***
  • Posts: 315
  • Respect: +97
Re: Chemistry Question Thread
« Reply #1797 on: March 07, 2017, 05:59:22 pm »
0
How do you add half equations together? I'm really bad at it :/

Balance the half equations first so there's the same number of electrons in both. After that, all you have to do is add the two equations together (combine everything on the reactants side and products side) and cancel the electrons on both sides :)
HSC 2017: English Adv (93) | Maths Ext 1 (99) | Maths Ext 2 (97) | Chemistry (95) | Physics (95)
ATAR: 99.85

beau77bro

  • Forum Obsessive
  • ***
  • Posts: 342
  • Respect: +6
Re: Chemistry Question Thread
« Reply #1798 on: March 09, 2017, 08:44:21 am »
0
Hey how does one write net ionic equations? I'm confused with the whole different sets of equations used, so there's half, complete, nuclear and net, are there any others I need to know?
thankyou

jakesilove

  • HSC Lecturer
  • Honorary Moderator
  • Part of the furniture
  • *******
  • Posts: 1941
  • "Synergising your ATAR potential"
  • Respect: +196
Re: Chemistry Question Thread
« Reply #1799 on: March 09, 2017, 09:10:07 am »
0
Hey how does one write net ionic equations? I'm confused with the whole different sets of equations used, so there's half, complete, nuclear and net, are there any others I need to know?
thankyou

Hey! Yep, those are the equations you'll need to be able to figure out. Net ionic equations essentially leave out spectator ions; other than that, it's just the complete equation. Half equations break the reaction up into reduction and oxidation halves (so one side should be adding electrons, one side should be losing electrons). Not sure whether you're looking for clarification or actual help, so if there's a specific equation that you're struggling with post it up and we can help you out!
ATAR: 99.80

Mathematics Extension 2: 93
Physics: 93
Chemistry: 93
Modern History: 94
English Advanced: 95
Mathematics: 96
Mathematics Extension 1: 98

Studying a combined Advanced Science/Law degree at UNSW