I would like some clarification on this as well! Someone told me that Na+ is extremely weak because it's the conjugate acid of NaOH, a strong base, is this right?
Sup,
Not sure if this has been answered before, but thinking about it like this should help:
I'll just take a strong acid HA as the example. So HA + water --> A- and hydronium. For HA to be a strong acid, it must ionize to completion in water. Hence if you set up an acidity constant Ka will be very high.
Now consider, the reverse of the equation, so: A- + hydronium --> HA + water. In this case, if A- was a strong conjugate base, then, it would accept the hydrogen and form HA, and hence its basicity constant would be high. So the problem with this is that you can't have a high Ka for one reaction, and a high Kb for its backwards reaction, because then you're not having complete ionization. Hence it should be: strong acid --> weak conjugate base, strong base--> weak conjugate acid, weak base --> strong conjugate acid, weak acid --> strong conjugate base.
So in the case of NaOH, which is a very strong base, we will have a very weak conjugate acid Na+. It's basically an inverse relationship. The higher the acidity, the lower the basicity. eg. HCl is a strong acid, Cl- is a weak conjugate base.
Hope this helps