Can i please have help with this question??
You can also do part ii) by comparing the K value at different temperatures
At 25
oC, 0.04 moles of N
2O
4 forms. Thus, 0.08 moles of NO
2 were reacted (2:1 ratio) and 0.132-0.08=0.052 moles are left. Concentration of both are the same as the moles as v=1L. So K at 25
oC is \(\frac{0.04}{(0.052)^2} = 14.79...\)
This tells us that when the temperature decreases from 100 --> 25
oC, K increases. So to oppose the decrease in temperature, the concentration of products has increased, ie. equilibrium has shifted to the right to produce more heat (by Le Chatelier). Because the forward reaction is the one which produces more heat, it is exothermic.
