Hi
why does the pH of identical concentrations of HCl and Acetic acid change by different amounts when diluted with the same volumes of water ??
thanks
It's got to do with strong/weak acids and LCP.
Strong Acid}+\ce{H2O(l)}\rightarrow\ce{H3O+(aq)}+\ce{Cl^{-}(aq)})
Let's assume that we have a 1L solution of HCl with pH 1.
It's a strong acid and will ionise completely. When you add 9L of water, you decreased the concentration of H+ by tenfold, and the pH will be 2.
Weak Acid}+\ce{H2O(l)}⇌\ce{H3O+(aq)}+\ce{F^{-}(aq)})
Let's assume that we have 1L of this weak HF acid with a pH of 3.
If I were to dilute with water, the equilibrium will shift to the right to produce more H3O+ and decrease pH. However, the volume of water has also increased and has lowered the concentration. So after adding 9L of water to our pH 3 HF acid, our resulting pH will be around 3-4 because it it had produced more H3O+ during diluting.
Thus, strong/weak acids have different pH changes in dilution.
Make sense?
