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October 19, 2025, 09:44:53 pm

Author Topic: HSC Chemistry Question Thread  (Read 1297709 times)  Share 

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MisterNeo

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Re: Chemistry Question Thread
« Reply #2685 on: August 27, 2017, 10:23:31 pm »
+9
Can someone pls explain why for q 12 2015 hsc the answer is a and not d?

Hey ;D
The top number represents the mass number, which is the total protons plus neutrons. The bottom number represents atomic number, which is the total protons.
Since the plutonium-239 gains X to become plutonium-241, we know that the protons haven't changed because it's still plutonium. So it must have gained neutrons to increase its mass number by 2.
Now plutonium-241 is unstable (too many neutrons), and decays into americium-241 by changing a neutron to a proton and an electron.
Think of a neutron as a proton combined with an electron (they cancel each other). To become a proton, it kicks out the electron to become positive. (This isn't scientifically correct but it's how I remember it)
Hence, the answer is A because X is a neutron and Y is an electron.
Hope this helps :D

Mathew587

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Re: Chemistry Question Thread
« Reply #2686 on: August 28, 2017, 05:23:00 pm »
+1
Oh right I see. It pretty much undergoes neutron bombardment. Thanks :)
HSC 2017- 90.58
English Adv: 85
Mathematics Adv: 89
Biology: 86
Chemistry: 81
Economics:86
Business Stud: 91

~ UNSW Economics/Science ~

justwannawish

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Re: Chemistry Question Thread
« Reply #2687 on: August 29, 2017, 06:18:14 pm »
+1
Hi!

Not too sure about the first question, sorry!

- Separating a variety of mixtures
- Intermolecular(dispersion/dipole-dipole/hydrogen) and Intramolecular(ionic/covalent/metallic) forces
- Development of the Periodic Table
- SOLUBILITY OF SALTS
- Diamond/Graphite comparison

Hope this helps!

Thank you for your help!

Is there a generally standard way to set out moles questions? With or without limiting reagents

Mod edit: Formatting
« Last Edit: August 29, 2017, 07:10:22 pm by 13cheungjn1 »

Natasha.97

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Re: Chemistry Question Thread
« Reply #2688 on: August 29, 2017, 07:26:53 pm »
+7
Thank you for your help!

Is there a generally standard way to set out moles questions? With or without limiting reagents

Mod edit: Formatting

Hi!
Usually, the question gives values that allow the moles to be determined for one particular species. I would set it out with the general formula (m/M), then the molar ratio between the known substance and the unknown. Refer to the questions below:

If 15.65g of Calcium Carbonate was completely decomposed by heat, what volume of carbon dioxide gas would be produced if measured at SLC?
Spoiler
-Equation: CaCO3(s) → CO2(g) + CaO(s)
- Mass (g) = 15.65g
- Molar Mass of CaCO3 = 40.08 + 12.01+ 48 = 100.09
- Moles (n) = m/M = 15.65/100.09 = 0.1564 mol
- n(CaCO3) : n(CO2) = 1 : 1, so n(CO2) = 0.1564 mol
∴ Volume of CO2 = 0.1564 × 24.8 = 3.88L at SLC

What volume of hydrogen gas at SLC would be produced if 10.00g of lithium metal was reacted with sulphuric acid?
Spoiler
Equation: 2Li(s) + H2SO4(s) →H2(g) + Li2SO4(aq)
- Mass (g) = 10.00g
- Molar Mass of Li = 6.941g/mol
- Moles (n) = m/M = 10.00/6.941 = 1.441 mol
- n(Li) : n(H2) = 2 : 1, so n(H2) =  1.441/2 = 0.7204
∴ Volume of H2 = 0.1564 × 24.8 = 3.88L at SLC

Hydrated sodium carbonate is represented by the formula Na2CO3 ∙ xH2O, where x is an integer. When 100.00 g of this compound was heated strongly to drive off the water, the anhydrous compound left behind had a mass of 37.04g. Calculate the number of water molecules, x, in one mole of hydrated sodium carbonate.
Spoiler
                          Na2CO3 ∙ xH2O → Na2CO3(s) + xH2O(g)
Water
- Mass (g) = 100.00 – 37.04 = 62.96g
- M (H2O) = (2 × 1.01) + 16.00 = 18.02g/mol
- Moles (n) = m/M = 62.96/18.02 = 3.495 mol

Sodium Carbonate
- Mass (g) = 37.04g
- Molar Mass (M) = (2 × 22.99) + 12.01 + (3 × 16.00) = 105.99g/mol
- Moles (n) = m/M =  37.04/105.99 = 0.349 mol

Ratio
n(H2O) : n(Na2CO3) = 3.495 : 0.349 = 10 : 1
x = 10
∴ 10 moles of water in one mole of hydrated sodium carbonate

Hope this helps
Life is weird and crazy as heck but what can you do?

caprese_

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Re: Chemistry Question Thread
« Reply #2689 on: August 30, 2017, 11:51:08 am »
+1
Hi,
answer is iii and iv. Why are there no hydrogen  bonds between the molecules?
Ty v much

MisterNeo

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Re: Chemistry Question Thread
« Reply #2690 on: August 30, 2017, 09:46:03 pm »
+7
Hi,
answer is iii and iv. Why are there no hydrogen  bonds between the molecules?
Ty v much

Hey ;D

Hydrogen bonding only occurs if two molecules have a hydrogen atom bonded to a highly electronegative atom (N, O, halogens).
Ethanol has a hydrogen bonded to an oxygen, which is partially positive because the oxygen is more electronegative and will pull the electrons closer to itself.
CHF3 has its hydrogen bonded to a carbon, which has almost the same electronegativity as hydrogen. This doesn't allow hydrogen bonding since the hydrogen isn't positively charged and will not attract to ethanol's oxygen.

Basically, you look at what the hydrogen is bonded with. :)

winstondarmawan

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Re: Chemistry Question Thread
« Reply #2691 on: September 01, 2017, 11:11:30 pm »
+1
Hello!
For the production of LDPE, I have come across some sources which say it is created with the absence of a catalyst, and other sources which say it is created with an organic catalyst.
Which is more correct and should be used in the HSC?
TIA.

Natasha.97

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Re: Chemistry Question Thread
« Reply #2692 on: September 01, 2017, 11:22:50 pm »
+8
Hello!
For the production of LDPE, I have come across some sources which say it is created with the absence of a catalyst, and other sources which say it is created with an organic catalyst.
Which is more correct and should be used in the HSC?
TIA.

Hi!

I've asked this exact question to my teacher, and they said that there is no catalyst in LDPE production. A peroxide initiator e.g. benzoyl peroxide is used, but it is not a catalyst as it becomes part of the polymer. In the production of HDPE, a Ziegler-Natta catalyst is used e.g. Titanium Chloride.

Hope this helps
« Last Edit: September 01, 2017, 11:37:25 pm by 13cheungjn1 »
Life is weird and crazy as heck but what can you do?

anotherworld2b

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Re: Chemistry Question Thread
« Reply #2693 on: September 02, 2017, 06:45:43 pm »
+1
I am not sure how to do this question. Can I have help please?

VanillaRice

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Re: Chemistry Question Thread
« Reply #2694 on: September 02, 2017, 07:15:54 pm »
+9
I am not sure how to do this question. Can I have help please?


n(NaOH) = cV = 0.0126 x 0.390 = 0.004914 mol
n(sulfuric acid) = 1/2 x n(NaOH) = 0.002457 mol
Dilution factor is 1000/25 = 40
n(sulfuric acid)intial = 0.024578 x 40 = 0.09828 mol
m(sulfuric acid) = 98g/mol x 0.09828 mol = 9.63144g
So, there was 9.63144g of actual sulfuric acid

Total mass = 19.6mL x 1.67g/mL = 32.732g

So, % mass of sulfuric acid = 9.63144/32.732 x 100 = 29.4%

Hope this helps :)



VCE 2015-16
2017-20: BSc (Stats)/BBiomedSc [Monash]

winstondarmawan

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Re: Chemistry Question Thread
« Reply #2695 on: September 03, 2017, 06:30:08 pm »
+1

MisterNeo

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Re: Chemistry Question Thread
« Reply #2696 on: September 03, 2017, 07:37:47 pm »
+8
Hello!
Can someone go through the thought processes for answering a question like Q1.
https://scontent-syd2-1.xx.fbcdn.net/v/t34.0-12/21291632_1316215258503994_317323894_n.jpg?oh=658bc156d33a2b45eb8b183a5415ef5c&oe=59AE7C18
TIA.

Hey :D
For questions like these, there isn't really a specific approach but you would need to know that:
-Addition monomers are usually unsaturated (double/triple C-C bonds).
-Condensation monomers are usually saturated (single C-C bonds)
So the answer can't be C.

After that, my main approach is to do trial-and-error to see what works, like try doing a quick sketch or do it visually. Also note that the monomers alternate each time. It just takes practice.  :)
« Last Edit: September 03, 2017, 07:40:58 pm by MisterNeo »

winstondarmawan

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Re: Chemistry Question Thread
« Reply #2697 on: September 03, 2017, 10:17:31 pm »
+1
Are we required to know the structural two-step reaction which shows how sulfuric acid acts as a catalyst?
(For hydration of ethene and dehydration of ethanol.)
Edit: Why do we need a water reaction medium for fermentation?
TIA.
« Last Edit: September 03, 2017, 10:29:14 pm by winstondarmawan »

MisterNeo

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Re: Chemistry Question Thread
« Reply #2698 on: September 03, 2017, 10:48:06 pm »
+8
Are we required to know the structural two-step reaction which shows how sulfuric acid acts as a catalyst?
(For hydration of ethene and dehydration of ethanol.)
Edit: Why do we need a water reaction medium for fermentation?
TIA.

In the HSC course, we don't need to know how it reacts with the catalyst. All you need to know is what the catalyst is.
Water is used because:
-Moist conditions
-It dissolves glucose because yeast is a powder form and can't do anything to another solid.
-Water dilutes the ethanol produced because yeast dies in high conc. of ethanol.



Aussie1Italia2

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Re: Chemistry Question Thread
« Reply #2699 on: September 05, 2017, 04:29:21 pm »
+1
Hi,

Can you please explain to me what validity is again? I'm trying to answer a past HSC paper question and its asking me to discuss the validity of a student's investigation.

Thank you!!!
HSC 2017:
English Standard
Mathematics
Biology
Chemistry
PDHPE
Italian Beginners

Hoping to do Neuroscience at Uni!