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January 03, 2026, 04:13:47 pm
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Author Topic: Bucket's Questions  (Read 57046 times)  Share 

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ed_saifa

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Re: Bucket's Questions
« Reply #120 on: March 09, 2008, 09:53:21 pm »
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wouldn't that be easier than letting it equal the inverse?
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Collin Li

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Re: Bucket's Questions
« Reply #121 on: March 09, 2008, 09:53:51 pm »
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Intersecting any of the two with is the best way to go about it. The inverses of each other intersect if they intersect with their axis of symmetry, which is . You don't need to find the inverse this way!

However, you will need a calculator to solve it explicitly.
« Last Edit: March 09, 2008, 10:02:22 pm by coblin »
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Glockmeister

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Re: Bucket's Questions
« Reply #122 on: March 09, 2008, 09:54:44 pm »
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And not in the Methods course.
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Re: Bucket's Questions
« Reply #123 on: March 09, 2008, 09:55:39 pm »
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solving in y=x is generally accepted, but sometimes there can be multiple (or infinite) solutions, such as a symmetry of y=x already exists:

(a quater circle)
which the reverse is itself... (infinite solutions)
« Last Edit: March 09, 2008, 09:57:41 pm by Mao »
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Collin Li

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Re: Bucket's Questions
« Reply #124 on: March 09, 2008, 09:56:14 pm »
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Quote from: Glockmeister on March 09, 2008, 09:54:44 pm
And not in the Methods course.

Knowing the axis of symmetry of inverses is in the Methods course. If you're referring to Newton's method, then yeah, you're right.
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Re: Bucket's Questions
« Reply #125 on: March 09, 2008, 09:57:21 pm »
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ah fair go, calculator it is then O_O.
thanks all of you.
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Re: Bucket's Questions
« Reply #126 on: March 10, 2008, 02:30:36 am »
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Quote from: coblin on March 09, 2008, 09:56:14 pm
Quote from: Glockmeister on March 09, 2008, 09:54:44 pm
And not in the Methods course.

Knowing the axis of symmetry of inverses is in the Methods course. If you're referring to Newton's method, then yeah, you're right.

Yeah I was referring to the Newton's method, just that you guys dived in with posts whilst I was writing that.
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Re: Bucket's Questions
« Reply #127 on: March 16, 2008, 12:42:42 pm »
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if find the value for y.
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ed_saifa

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Re: Bucket's Questions
« Reply #128 on: March 16, 2008, 12:45:24 pm »
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y= ex^2
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bucket

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Re: Bucket's Questions
« Reply #129 on: March 16, 2008, 01:04:12 pm »
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how did you work that out? O_O
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Re: Bucket's Questions
« Reply #130 on: March 16, 2008, 01:28:28 pm »
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from the log laws:




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Re: Bucket's Questions
« Reply #131 on: March 16, 2008, 02:20:28 pm »
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If , then y is equal to?
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Re: Bucket's Questions
« Reply #132 on: March 16, 2008, 03:01:41 pm »
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by the same token







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Re: Bucket's Questions
« Reply #133 on: March 16, 2008, 05:18:04 pm »
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the inverse of function is
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Re: Bucket's Questions
« Reply #134 on: March 16, 2008, 05:26:03 pm »
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VCE Outline:
2007:   Accounting [48]

2008:   English [44], Maths Methods [50], Specialist Maths [41], Chemistry [50], Physics [44]

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