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January 03, 2026, 05:56:12 am

Author Topic: Bucket's Questions  (Read 57021 times)  Share 

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Mao

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Re: Bucket's Questions
« Reply #135 on: March 16, 2008, 05:26:39 pm »
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now it will be a lot easier :D
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dcc

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Re: Bucket's Questions
« Reply #136 on: March 16, 2008, 05:26:56 pm »
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Swapping the x & y coordinates:








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Re: Bucket's Questions
« Reply #137 on: March 16, 2008, 06:49:28 pm »
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ahh are those answers the same? O_O
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Collin Li

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Re: Bucket's Questions
« Reply #138 on: March 16, 2008, 06:50:58 pm »
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Yes (the proof is above: going from unknown's answer to dcc's answer) :)

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Re: Bucket's Questions
« Reply #139 on: March 16, 2008, 09:39:08 pm »
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ohh thanks alot everyone!
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bucket

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Re: Bucket's Questions
« Reply #140 on: March 19, 2008, 09:47:52 pm »
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an extremely easy question.
Find of
I don't understand the part.
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Neobeo

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Re: Bucket's Questions
« Reply #141 on: March 19, 2008, 10:01:37 pm »
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an extremely easy question.
Find of
I don't understand the part.

Basically they are just limiting the domain for you, in effect simplifying the equation, since you cannot divide anything by zero. Since they let , then , so you will not be dividing by zero. This means that you can just divide the whole thing to make which should be a lot simpler.
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Re: Bucket's Questions
« Reply #142 on: March 19, 2008, 10:15:37 pm »
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You know, I've never thought about the in that way before. I would've had just ran straight to the quotient rule.
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Re: Bucket's Questions
« Reply #143 on: March 19, 2008, 10:39:53 pm »
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That explains why I got that question wrong :P, thanks a lot neobeo.
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Re: Bucket's Questions
« Reply #144 on: March 20, 2008, 04:53:53 pm »
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in a question such as the one above, how do you prove that ?
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Collin Li

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Re: Bucket's Questions
« Reply #145 on: March 20, 2008, 06:00:48 pm »
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in a question such as the one above, how do you prove that ?

You don't prove it. It is just a specified domain. It's just telling you, do this task for the domain .

Mao

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Re: Bucket's Questions
« Reply #146 on: March 20, 2008, 08:27:38 pm »
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This is a division operation, and the absolute no-no is to divide something by 0

so is undefined when



is that what you wanted to know?
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AppleXY

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Re: Bucket's Questions
« Reply #147 on: March 20, 2008, 08:34:47 pm »
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You know, I've never thought about the in that way before. I would've had just ran straight to the quotient rule.

Yeah, using the quotient rule is not most efficient method to diff in this case.

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Re: Bucket's Questions
« Reply #148 on: March 20, 2008, 08:35:08 pm »
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yeah thanks mao that makes sense.
theres questions in the exercise book asking that =\
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Mao

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Re: Bucket's Questions
« Reply #149 on: March 20, 2008, 08:46:57 pm »
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You know, I've never thought about the in that way before. I would've had just ran straight to the quotient rule.

Yeah, using the quotient rule is not most efficient method to diff in this case.

is algebraicly equivalent to
but you need to include that in your final solution

using the quotient rule avoids having to attach this restraint, as the denominator will imply that it is the case

however, just to be safe, always state the domain of wierd looking equations =D

another thing to be careful with is differentiability... that's a whole new can of worms :P
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