most awesome question thread :)

[TrueTears]

lifesaver

btw howd u break it down to that, ive tried n failed

Long division.

Let

[superflya]

got it. thanks

[superflya]

why cant i do this >.<



sin inverse?

[/0]

In general if you see anything of the form , try the substitution ,   

Let with , then


















With try ,

With try ,

[Ahmad]

That's a perfectly reasonable approach, another approach would be noticing that the x in the numerator is the derivative of x^2 upto a constant, which suggests the substitution u = x^2.

[Damo17]

why cant i do this >.<



sin inverse?

x is on top of the fraction so it can not be sin inverse.

Let

  so

so

[/0]

That's a perfectly reasonable approach, another approach would be noticing that the x in the numerator is the derivative of x^2 upto a constant, which suggests the substitution u = x^2.

ah, of course! thanks ahmad

*facepalm*

[Damo17]

That's a perfectly reasonable approach, another approach would be noticing that the x in the numerator is the derivative of x^2 upto a constant, which suggests the substitution u = x^2.

ah, of course!

*facepalm*

Too much 'Stewart Calculus' would be to blame. 

[/0]

That's a perfectly reasonable approach, another approach would be noticing that the x in the numerator is the derivative of x^2 upto a constant, which suggests the substitution u = x^2.

ah, of course!

*facepalm*

Too much 'Stewart Calculus' would be to blame. 

Lol yes, now I'm a mindless integrating drone XD

[Ahmad]

In general if you see anything of the form , try the substitution

This is a quality suggestion, certainly something to look for. It's good to do integrals in many different ways, gives you an idea of what works and why.

[superflya]

thanks guys

[superflya]

differentiate

hence verify that

[kamil9876]

let u=cosx















and now antidifferentiate both sides

[brightsky]

I suggest you reading: http://vcenotes.com/forum/index.php/topic,7092.0.html. May help a bit.

[superflya]

sweet