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October 03, 2025, 06:32:32 am
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Author Topic: TyErd's questions  (Read 42834 times)  Share 

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TyErd

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Re: TyErd's questions
« Reply #105 on: April 26, 2010, 12:01:45 pm »
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following on from the previous question, how would you solve

if you can can you show me how to do it with complementary angles and identites please :)
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the.watchman

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Re: TyErd's questions
« Reply #106 on: April 26, 2010, 12:05:31 pm »
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Quote from: TyErd on April 26, 2010, 12:01:45 pm
following on from the previous question, how would you solve

if you can can you show me how to do it with complementary angles and identites please :)

By definition (and a unit circle diagram), from you previous post :)
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Stroodle

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Re: TyErd's questions
« Reply #107 on: April 26, 2010, 12:08:07 pm »
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Using the compound angle formula:





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the.watchman

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Re: TyErd's questions
« Reply #108 on: April 26, 2010, 12:09:08 pm »
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Quote from: Stroodle on April 26, 2010, 12:08:07 pm
Using the compound angle formula:







Erm ... it's miles easier to use the complementary angle formulas... :P
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Remember, remember the 5th of November

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2011 - Eng - Phys - Chem - Spesh - Latin - UMAT
ATAR - 99.00+ plz... :)

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TyErd

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Re: TyErd's questions
« Reply #109 on: April 26, 2010, 12:11:49 pm »
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I just realised I had none of these formulas on my cheat sheet. Thanks!
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Stroodle

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Re: TyErd's questions
« Reply #110 on: April 26, 2010, 12:14:13 pm »
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Quote

Erm ... it's miles easier to use the complementary angle formulas... :P

For sure. I just thought he was asking for a different way to do it.
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the.watchman

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Re: TyErd's questions
« Reply #111 on: April 26, 2010, 12:16:18 pm »
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Quote from: Stroodle on April 26, 2010, 12:14:13 pm

Quote

Erm ... it's miles easier to use the complementary angle formulas... :P

For sure. I just thought he was asking for a different way to do it.

Quote from: TyErd on April 26, 2010, 12:01:45 pm
if you can can you show me how to do it with complementary angles and identites please :)

Really? :D
(jks jks)
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Remember, remember the 5th of November

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2011 - Eng - Phys - Chem - Spesh - Latin - UMAT
ATAR - 99.00+ plz... :)

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TyErd

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Re: TyErd's questions
« Reply #112 on: April 26, 2010, 12:24:59 pm »
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Hm.. the cambridge essentials book doesn't have any double angle formulae questions. Anyone have a tricky double angle problem that will help me revise for the SAC?
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TyErd

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Re: TyErd's questions
« Reply #113 on: April 26, 2010, 01:48:28 pm »
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I'm not 100% sure about this one. I know that its either A or E. When it says , is the 1 a vertical translation or is that part of the horizontal?
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Blakhitman

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Re: TyErd's questions
« Reply #114 on: April 26, 2010, 02:10:25 pm »
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f(2x-1): DIlation by factor of 1/2 along the x-axis. horizontal translation of 1/2 units to the right,
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TyErd

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Re: TyErd's questions
« Reply #115 on: April 26, 2010, 02:13:52 pm »
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ok, so for it to be a vertical translation it would be written as: f(2x-1)-1 yeah?
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Blakhitman

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Re: TyErd's questions
« Reply #116 on: April 26, 2010, 02:29:03 pm »
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yep!

I'd recommend remembering this:

Quote from: Blakhitman on April 24, 2010, 04:31:58 pm
Remember these:

  • dilation of along the x-axis.
  • dilation of "n" along y-axis.
  • reflection on the x-axis.
  • reflection on the y-axis.
  • translation of "a" units to the right.
  • translation of "a" units to the left.
  • translation of "k" units up.
  • translation of "k" units down.
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TyErd

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Re: TyErd's questions
« Reply #117 on: April 26, 2010, 02:42:21 pm »
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thnx!
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Blakhitman

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Re: TyErd's questions
« Reply #118 on: April 26, 2010, 02:47:11 pm »
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Also note in you previous example, f(2x-1) to get it in the form to determine transformations, it's easier to factorise:
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TyErd

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Re: TyErd's questions
« Reply #119 on: April 26, 2010, 02:54:26 pm »
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yup thnx!
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"Don’t ever let somebody tell you you can’t do something, not even me.  Alright?  You got a dream, you gotta protect it.  People can’t do something themselves, they wanna tell you you can’t do it.  If you want something, go get it, period." - Chris Gardner
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