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September 28, 2026, 12:03:12 am

Author Topic: TyErd's questions  (Read 55963 times)  Share 

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TyErd

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Re: TyErd's questions
« Reply #195 on: May 28, 2010, 06:49:59 pm »
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error in your latex brightsky
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brightsky

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Re: TyErd's questions
« Reply #196 on: May 28, 2010, 06:50:37 pm »
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error in your latex brightsky

Fixed. :D (Sorry about that :p)
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TyErd

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Re: TyErd's questions
« Reply #197 on: May 28, 2010, 07:16:45 pm »
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awesome, thnx i get it now! :)
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moekamo

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Re: TyErd's questions
« Reply #198 on: May 28, 2010, 07:25:30 pm »
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oh shit sorry forgot dy/dx

so correct answer to this to gain full marks is





     
     

?

wait,

i think you forgot part of the product rule in your workings there tyerd :S
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TyErd

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Re: TyErd's questions
« Reply #199 on: May 28, 2010, 10:17:45 pm »
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what i did was apply the chain rule to the 2nd term. I dunno is that wrong?
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TyErd

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Re: TyErd's questions
« Reply #200 on: May 28, 2010, 10:38:18 pm »
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I am soo bloody confused right now. I know I can use product rule or quotient rule if i wanted to but what about the way i did it?
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m@tty

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Re: TyErd's questions
« Reply #201 on: May 28, 2010, 11:32:45 pm »
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Wait, I'm sorry for not seeing it earlier.  You forgot to use the product rule. All you did was find the derivative of both parts, but according to the quotient rule you had to multiply each derivative by the other function...

.

You omitted the parts I bolded.
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TyErd

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Re: TyErd's questions
« Reply #202 on: May 28, 2010, 11:35:00 pm »
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Ohh okayys thnx!

Also Differentiate:
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m@tty

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Re: TyErd's questions
« Reply #203 on: May 28, 2010, 11:42:04 pm »
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.

Which, using a double angle formula, can be simplified to:

.

But I don't think you need to know this :P Spesh stuff...
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TyErd

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Re: TyErd's questions
« Reply #204 on: May 28, 2010, 11:48:50 pm »
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i dunno, theres a bit of it in the essentials book, The spesh teacher at my school makes the SACs and she's a bitch because she wants her spesh/methods students to get the top scores so she adds spesh shit to the methods SAC.

i dont get how you did the first line, im confused with the squared bit mainly.

 
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m@tty

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Re: TyErd's questions
« Reply #205 on: May 29, 2010, 12:04:57 am »
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Okay, .

So use the chain rule with .





Sub back for and .

.
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TyErd

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Re: TyErd's questions
« Reply #206 on: May 29, 2010, 12:17:50 am »
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okay thnx i get it :)
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TyErd

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Re: TyErd's questions
« Reply #207 on: May 29, 2010, 02:42:00 am »
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Differentiate:

« Last Edit: May 29, 2010, 02:44:16 am by TyErd »
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moekamo

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Re: TyErd's questions
« Reply #208 on: May 29, 2010, 06:18:52 am »
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let

also

so
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Re: TyErd's questions
« Reply #209 on: May 29, 2010, 09:08:26 am »
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You could do that, or:

Considering that is a constant

Then



This employs the derivative "trick" of
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