Questions

[Mikey123]

Love ya

[Noblesse]

^ thats from the essential book right? are you going to use that for your bound reference?

Yeah it's from essential, but no, I made a bound reference book throughout the year - saved me a lot of hassle now! (more time for prac exams!)

[Mikey123]

Okay anyone got a page with bearing formulas and hints?

I think my reference lacks that.

[vce01]

neap exam 1 06 - q10 on core.

cant it be 1/y as well?

[*Roxxii*]

neap exam 1 06 - q10 on core.

cant it be 1/y as well?

For data in that sort of shape, yes, either x^2, Log(y) or 1/y can be used to linearise the data.
But not all 3 give the same effect, some will linearise the data more than others.

For the question, it is asking which will be MOST likely to linearise the data.
From the graph, we can clearly see that the shape of the points resembles a parabola, not a hyperbolic function or a log function. Leaving you with the answer of C. x^2

Do you do methods by any chance?
I have only recently picked up that if you are aware of what each graph looks like, ie hyperbolas, logs, parabolas...
It is very useful in determining which transformation to use

[Noblesse]

So, if the graph looks like a log graph then a log function will be the most likely to linear the graph the best? How would you know to log(x) or log(y)?

[vce01]

neap exam 1 06 - q10 on core.

cant it be 1/y as well?

For data in that sort of shape, yes, either x^2, Log(y) or 1/y can be used to linearise the data.
But not all 3 give the same effect, some will linearise the data more than others.

For the question, it is asking which will be MOST likely to linearise the data.
From the graph, we can clearly see that the shape of the points resembles a parabola, not a hyperbolic function or a log function. Leaving you with the answer of C. x^2

Do you do methods by any chance?
I have only recently picked up that if you are aware of what each graph looks like, ie hyperbolas, logs, parabolas...
It is very useful in determining which transformation to use

yeah i do methods, but not too good at it.

they wouldn't ask that type of question then though would they? further students not doing methods otherwise will be disadvantaged

another question...say for an example you're given a curve, like a parabola over the domain of R+ and a point of umm (4,16) is given. is it necessary for us to know how to find the rule connecting y and x and if so, how would you go about finding it?

[*Roxxii*]

So, if the graph looks like a log graph then a log function will be the most likely to linear the graph the best? How would you know to log(x) or log(y)?

Hmm, i have not yet established that (me= phail)
But we have a reference book, so there is no need to learn which transformations to use off by heart. yayyy

But i for a couple of the exams i did, i forgot to bring my reference book to the library so i actually worked out my answers using this method, without any reference material, and it worked for me lol. (or maybe i was just lucky...hmm!)
So yeah, ruled out a few questions first, but it was still a little bit of guesswork.

I might look into it a bit more after my exams when i have time

[*Roxxii*]

yeah i do methods, but not too good at it.

they wouldn't ask that type of question then though would they? further students not doing methods otherwise will be disadvantaged

another question...say for an example you're given a curve, like a parabola over the domain of R+ and a point of umm (4,16) is given. is it necessary for us to know how to find the rule connecting y and x and if so, how would you go about finding it?

This seems like Graphs and relations...hmm...
Usually, they will give you a question with like in your example, a parabola. (on the axis, x and y)
Then they will give a set of graphs with the axis labled y and x^2, with different points on it.
You will be asked which one is a correct representation of the given parabola.
Or they might do it the other way around.

Ok, i would first find the equation of the parabola, which the point of (4,16) lies on, giving you y=x^2
Then to find out which points lie on the graph with axis labeled y and x^2, simply delete the ^2 from your equation.
In this case ( u have given an easy example ) The y=x^2 simply turns into y=x
You can then sub in certain the x-values into the equation, giving you the y-value...to find the co-ordinates that match on of the answers.

ie, if you were given 5 choices.
All with y and x^2 on the axis, but with the different points...
A. (2,4)  B. (2,8) C. (2,2) D. (4,2) E.  (4,16)

Your answer would be C. (2,2) as this point lies on the graph of y=x.

I hope this was what you were asking about, and that i havent written all this for nothing lolz
But this was a question is similar to a question that was pretty poorly handled on last years exam.
So i suggest people to learn this, as i am predicting another question of this sort in Graphs and relations today lolz

[jsimmo]

Can someone please tell me how the answer in NEAP 2005 (exam 2) question

1 bi. = (0,70) **I got (12,66)
1 bii. = (12,66) **I got (42.85, 42.85)

I think they stuffed up their answers? Agreed?