Exam Suggested Solutions

[H2SO4]

side chain confused me, i was unsure if they wanted Z group or not, but it said GROUP so i presummed the Z group, which had a hydroxy.

exam had poor wording.

[bucket]

There was no carboxy group on the side chain >.< I cant remember exactly but the chain was like CH2OH, ie. hydroxy.

Amine and Carboxy groups are on the backbone of the amino acid, not the side chain.

[monicak]

why isnt it 'carboxy'

http://www.brinkmann.com/applications/images/molecular_structure/serine.gif
There's no carboxyl functional group in the side chain.. The side chain is the part coming down from the central carbon in the diagram

[bucket]

ROFL hey I was right about the side chain

[infraredismybitch]

oh poor mao
cant answer my simple little question
ill admit i lost a mark, school boy error.
oh well, still doesnt mean u can answer my question does it?
; )

Let me repeat:

You are cocky, but unfortunately for you, it doesn't save you a mark. Nor does this bragging of knowledge outside of the course help you with VCE Chemistry. What is the point of asking a 5-year old child who has only learnt addition how to calculate 5x6 (without explaining the 'x' operation)?

let me repeat,
ill admit i lost a mark, school boy error.
can you answer my question?

[Aba]

you are really cokky, go get a life u loser and stop dreaming about chem

[chem-nerd]

unfortunately infraredismybitch you asked for all the structural formulas for a cylcoketone of C5H10O of which Mao gave you all five

just because 4 of these have two stereoisomers each (which is not covered in VCE chemistry) doesnt make you somehow a genius who needs to belittle others

[bucket]

Sorry to burst everyones bubble, but there was a double dilution! No matter wat anyone says, those who don't believe are in denial.

I presumed the double dilution didn't matter, because whether the solution is diluted or not, there is the same mol in it :S.
The only factor I remember using is the pipette factors(ie, 25mL aliquot from the 1L solution). (btw before answering that question I converted the conc (mg/L was it?) into mol so i ignored the dilution factors)

[Aba]

Sorry to burst everyones bubble, but there was a double dilution! No matter wat anyone says, those who don't believe are in denial.

I presumed the double dilution didn't matter, because whether the solution is diluted or not, there is the same mol in it :S.
The only factor I remember using is the pipette factors(ie, 25mL aliquot from the 1L solution). (btw before answering that question I converted the conc (mg/L was it?) into mol so i ignored the dilution factors)

but 2 aliqouts were taken

[enwiabe]

infrared, I kindly request that you play nicely. Consider this a first warning.

[H2SO4]

ok my advice to all;

- quit worrying about unit 3, it's over

- start u're unit 4

 

[Aba]

ok my advice to all;

- quit worrying about unit 3, it's over

- start u're unit 4

 

no can do, there was a double dilution!

[Collin Li]

unfortunately infraredismybitch you asked for all the structural formulas for a cylcoketone of C5H10O of which Mao gave you all five

just because 4 of these have two stereoisomers each (which is not covered in VCE chemistry) doesnt make you somehow a genius who needs to belittle others

I believe there are 7, unless the last one doesn't count as a "cyclic ketone."

* cyclopentanone
* 3-methylcyclobutanone
* 2-methylcyclobutanone (2 stereoisomers)
* 2-ethylcyclopropanone (2 stereoisomers)
* 2,2-dimethylcyclopropanone
* 2,3-dimethylcyclopropanone (3 stereoisomers)
* acetocyclopropane (not sure how to systematically name this one)

Total: 11

[bucket]

Sorry to burst everyones bubble, but there was a double dilution! No matter wat anyone says, those who don't believe are in denial.

I presumed the double dilution didn't matter, because whether the solution is diluted or not, there is the same mol in it :S.
The only factor I remember using is the pipette factors(ie, 25mL aliquot from the 1L solution). (btw before answering that question I converted the conc (mg/L was it?) into mol so i ignored the dilution factors)

but 2 aliqouts were taken

Was there? I can't even remember, if there were two aliquot you would need to use the dilution factor once :S.

[Aba]

Sorry to burst everyones bubble, but there was a double dilution! No matter wat anyone says, those who don't believe are in denial.

I presumed the double dilution didn't matter, because whether the solution is diluted or not, there is the same mol in it :S.
The only factor I remember using is the pipette factors(ie, 25mL aliquot from the 1L solution). (btw before answering that question I converted the conc (mg/L was it?) into mol so i ignored the dilution factors)

but 2 aliqouts were taken

Was there? I can't even remember, if there were two aliquot you would need to use the dilution factor once :S.

 a dilution and an aliqout factor