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October 04, 2025, 08:08:31 pm
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Author Topic: TrueTears question thread  (Read 66996 times)  Share 

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TonyHem

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Re: TrueTears question thread
« Reply #360 on: May 21, 2009, 09:42:46 pm »
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it's not in spesh :l
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BlueYoHo

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Re: TrueTears question thread
« Reply #361 on: May 21, 2009, 09:51:14 pm »
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Nah but even the partial fractions stuff. It was like 20 lines. Intimidating.

We haven't started it yet though, so hopefully it's easier then it looks.
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TrueTears

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Re: TrueTears question thread
« Reply #362 on: May 21, 2009, 09:56:41 pm »
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Quote from: BlueYoHo on May 21, 2009, 09:51:14 pm
Nah but even the partial fractions stuff. It was like 20 lines. Intimidating.

We haven't started it yet though, so hopefully it's easier then it looks.
over9000 likes to making long workings :P
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Over9000

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Re: TrueTears question thread
« Reply #363 on: May 21, 2009, 09:58:29 pm »
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I pride myself in making an easy 2 line question into 20 lines of working so it looks better.
Jks, it was just a long question.
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BlueYoHo

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Re: TrueTears question thread
« Reply #364 on: May 21, 2009, 09:59:44 pm »
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lol
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dejan91

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Re: TrueTears question thread
« Reply #365 on: May 26, 2009, 12:34:30 am »
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Quote from: Over9000 on May 21, 2009, 09:58:29 pm
I pride myself in making an easy 2 line question into 20 lines of working so it looks better.

Haha true that :P
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TrueTears

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Re: TrueTears question thread
« Reply #366 on: June 12, 2009, 08:46:44 pm »
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The region bounded by the graph of the x axis , the y axis and the line x = 4 is rotated about the y axis. Find the volume generated.

Thanks.
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hyperblade01

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Re: TrueTears question thread
« Reply #367 on: June 12, 2009, 10:24:43 pm »
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My first attempt at using latex so I do apologise. Also may not be the best explanation as I haven't done specialist for a week and a half but I hope it helps:



When
When

Taking into account the restriction of x=4 you have to break up the graph so find the volume between y=1/5 and y=1/3





Between y = 0 and y = 1/5 and x = 4 there is a rectangle so to find the volume its just Area of circle X height






Add the two volumes and you get cubic units


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TrueTears

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Re: TrueTears question thread
« Reply #368 on: June 12, 2009, 10:26:29 pm »
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Thanks, was just thinking about breaking it up right now :)
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TrueTears

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Re: TrueTears question thread
« Reply #369 on: June 12, 2009, 11:34:01 pm »
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If and where , then is equal to? (In terms of A and B)
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kamil9876

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Re: TrueTears question thread
« Reply #370 on: June 12, 2009, 11:50:35 pm »
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Re: TrueTears question thread
« Reply #371 on: June 12, 2009, 11:54:36 pm »
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Thanks kamil but that has already been answered.
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kamil9876

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Re: TrueTears question thread
« Reply #372 on: June 13, 2009, 12:01:41 am »
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oh right, and now the next question:



Quote from: TrueTears on June 12, 2009, 11:34:01 pm
If and where , then is equal to? (In terms of A and B)
You should think of this in a geometrical-sort-of-way:

since the graph is symetrical about the y-axis

because again symmetrical about the y-axis however flipped over. tan(x)=-tan(-x).

Therfore out integral:





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TrueTears

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Re: TrueTears question thread
« Reply #373 on: June 13, 2009, 01:18:44 am »
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Awesome thanks.

The section of a straight line with equation between and is to be rotated about the y axis to form a container. What is the exact area of the water surface when the container is filled with of water?
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kamil9876

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Re: TrueTears question thread
« Reply #374 on: June 13, 2009, 01:48:11 am »
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edit: did the problem for x-axis :P

« Last Edit: June 13, 2009, 02:00:53 am by kamil9876 »
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