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December 21, 2025, 06:18:48 pm

Author Topic: VCE Methods Question Thread!  (Read 5843330 times)  Share 

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generalkorn12

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Re: VCE Methods Question Thread!
« Reply #1080 on: October 25, 2012, 02:30:08 pm »
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Could anyone tell me how to interpret this question, the worked solution is really vague.


BubbleWrapMan

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Re: VCE Methods Question Thread!
« Reply #1081 on: October 25, 2012, 02:34:38 pm »
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Try drawing a Venn diagram?
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Re: VCE Methods Question Thread!
« Reply #1082 on: October 25, 2012, 02:47:43 pm »
+3
We have events P and Q.
We know that this statement is true.

We want them to be independent events. In other words we want: (the event Q has no effect on event P). Anyway, if they're independent then this means .

From a Venn diagram, we can see that

Given that , this means that

Solve for Pr(P), we get

TrueTears

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Re: VCE Methods Question Thread!
« Reply #1083 on: October 25, 2012, 04:23:15 pm »
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Just providing another perspective:

P(P)P(Q) = P(P')P(Q) [Since if P is independent with Q then P' is independent with Q, very easy to prove. In fact if P is a RV, then any function of P, say g(P) is also independent with Q, and if we assume Q is also a RV, then g(P) and h(Q) are also independent for any functions g and h, independence is a very powerful result :D]

Assuming P(Q) > 0

P(P) = P(P')

P(P') = 1-P(P)

P(P) - (1-P(P)) = 0

P(P) = 1/2
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Re: VCE Methods Question Thread!
« Reply #1084 on: October 26, 2012, 01:13:53 pm »
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When i type nCr(5,3) on CAS, it gives me 10. But isn't that equal to (5x4x3x2x1)/(3x2x1)=20???

I'm forgetting something aren't i?
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Re: VCE Methods Question Thread!
« Reply #1085 on: October 26, 2012, 01:33:07 pm »
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When i type nCr(5,3) on CAS, it gives me 10. But isn't that equal to (5x4x3x2x1)/(3x2x1)=20???

I'm forgetting something aren't i?

generalkorn12

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Re: VCE Methods Question Thread!
« Reply #1086 on: October 26, 2012, 04:12:25 pm »
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Thanks for that Lassered and TrueTears!! I appreciate getting different perspectives on approaching a question.  :D

I've just got one more problem involving General Solutions;

For the question attached, I'm having trouble understanding where that formula could be derived from...

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aishuwa1995

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Re: VCE Methods Question Thread!
« Reply #1088 on: October 26, 2012, 04:40:45 pm »
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Hi, can someone please tell me how to do this question?  ???
tech-free
« Last Edit: October 26, 2012, 04:42:29 pm by thiskid »

TrueTears

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Re: VCE Methods Question Thread!
« Reply #1089 on: October 26, 2012, 04:49:35 pm »
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h'(x) = (n/x-1)x^ne^{-x}

stationary point when x = n.

h''(n) < 0 since n is a positive integer

so local max
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aishuwa1995

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Re: VCE Methods Question Thread!
« Reply #1090 on: October 26, 2012, 04:56:54 pm »
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h'(x) = (n/x-1)x^ne^{-x}

stationary point when x = n.

h''(n) < 0 since n is a positive integer

so local max

I don't understand how the quotient rule can give that h'(x)? (I get that when I use my CAS but it's an exam 1 question)

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Re: VCE Methods Question Thread!
« Reply #1091 on: October 26, 2012, 04:59:03 pm »
+1
h(x) = x^n e^{-x}

h'(x) = nx^{n-1} e^{-x} - x^n e^{-x} = x^ne^{-x} (nx^{-1} -1)
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Re: VCE Methods Question Thread!
« Reply #1092 on: October 26, 2012, 05:25:49 pm »
+1
If you wanted to use the quotient rule, you can still get the same answer that TT got out using the product rule like this:




aishuwa1995

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Re: VCE Methods Question Thread!
« Reply #1093 on: October 26, 2012, 05:34:54 pm »
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got it  :D thanks TrueTears and laseredd

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Re: VCE Methods Question Thread!
« Reply #1094 on: October 26, 2012, 07:05:10 pm »
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Got stuck with this:

integrate sin^2(x) using integration by parts

can someone please help ?!
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