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October 18, 2025, 04:49:09 am

Author Topic: VCE Methods Question Thread!  (Read 5742772 times)  Share 

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lzxnl

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Re: VCE Methods Question Thread!
« Reply #2205 on: July 09, 2013, 02:26:39 pm »
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Well it DOES fit the domain, the function is just zero there.

That means the flowers are guaranteed to survive past 1.5 days; integrating your function from 1.5 to infinity would yield 1.
So ok, you're really just finding the probability the flowers survive at least 4.5 days in total. That's easy.
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Sanguinne

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Re: VCE Methods Question Thread!
« Reply #2206 on: July 09, 2013, 03:52:02 pm »
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Well it DOES fit the domain, the function is just zero there.

That means the flowers are guaranteed to survive past 1.5 days; integrating your function from 1.5 to infinity would yield 1.
So ok, you're really just finding the probability the flowers survive at least 4.5 days in total. That's easy.

Thanks, got the right answer now  ;D
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jono88

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Re: VCE Methods Question Thread!
« Reply #2207 on: July 09, 2013, 06:19:46 pm »
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Can someone explain how to obtain the period of 60sin{(5t-1)pi/ 2}

Lasercookie

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Re: VCE Methods Question Thread!
« Reply #2208 on: July 09, 2013, 06:33:27 pm »
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Can someone explain how to obtain the period of 60sin{(5t-1)pi/ 2}
So expand it out into the form you recognise,

So hence

clıppy

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Re: VCE Methods Question Thread!
« Reply #2209 on: July 11, 2013, 01:20:06 pm »
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I'm having some trouble with part a) of this question. I'm not really sure how to begin solving it.

Also, when the question has variables and says that these are constants are these important details? Do they affect how you derive the equation?
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Re: VCE Methods Question Thread!
« Reply #2210 on: July 11, 2013, 01:43:21 pm »
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When you differentiate an expression that has constants in it, you can think of it as differentiating it as if the constants were some number, for example . It just means that for any expression we get, that value (the constant) isn't going to change as (well our independent variable) changes.
e.g. . For any value of , this holds.

For part a, Hint: Expand the expression out first.
Spoiler

Now we need to know what values can take. To find the largest value of this fraction we need to minimise the denominator. So first we look at . The smallest this can be is when , we have . Which means , and so . So our upper bound is (non inclusive).

Now to minimise the fraction we need to maximise the denominator, which in turn means we need to maximise . As , . . Now dividing by a really large number will give us a really small number, that is approaching zero. . So our lower bound is (non inclusive).

That is we have .
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clıppy

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Re: VCE Methods Question Thread!
« Reply #2211 on: July 11, 2013, 01:51:50 pm »
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For part a, Hint: Expand the expression out first.

You lost me in the middle, how did you get from the first step to the second step, where did the come from?
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b^3

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Re: VCE Methods Question Thread!
« Reply #2212 on: July 11, 2013, 02:01:36 pm »
+1
It's a little trick to expanding it out, you could also long divide.

In the above, we want to form the expression we have in the denominator on the top, so that we can cancel part of it down to get a constant. So to do this what do we need to add to to get ? right? But we need the expression to be equal to the line before it, so to do this if we add we need to also minus as well. Which is how we get to , as this is the same as .

EDIT: I guess this is how you would do it if you were to long divide.

« Last Edit: July 11, 2013, 02:05:54 pm by b^3 »
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clıppy

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Re: VCE Methods Question Thread!
« Reply #2213 on: July 11, 2013, 02:10:22 pm »
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Ohh okay, the long division helped explain what you were trying to achieve
Thanks b^3!
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Re: VCE Methods Question Thread!
« Reply #2214 on: July 11, 2013, 02:37:30 pm »
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The volume of milk in a 1-litre carton is normally distributed  with a mean of 1.000 litres and a standard deviation of 0.006 litres. A randomly selected carton is known to have more than 1.004 litres. Find the probability, correct to 4 decimal places that it has less than 1.011 litres.

Answer apparently is 0.8676
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darklight

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Re: VCE Methods Question Thread!
« Reply #2215 on: July 11, 2013, 02:47:25 pm »
+1
The volume of milk in a 1-litre carton is normally distributed  with a mean of 1.000 litres and a standard deviation of 0.006 litres. A randomly selected carton is known to have more than 1.004 litres. Find the probability, correct to 4 decimal places that it has less than 1.011 litres.

Answer apparently is 0.8676

This is conditional probability. So find the prob of carton having less than 1.011 litres given that it is more than 1.004 litres. So, therefore, it will be the prob between 1.004 and 1.011 litres divided by probability greater than 1.004 litres.
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Re: VCE Methods Question Thread!
« Reply #2216 on: July 11, 2013, 03:18:14 pm »
+1
i get 0.8678
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Re: VCE Methods Question Thread!
« Reply #2217 on: July 11, 2013, 06:45:16 pm »
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I'm having trouble understanding what the question is asking or what it's asking me to find.
The answer is apparently A but I don't know why.
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lzxnl

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Re: VCE Methods Question Thread!
« Reply #2218 on: July 11, 2013, 07:35:32 pm »
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For angle between two curves, tan theta =
So
And at x = 0
Plugging into formula, tan theta = (2-1)/(1+1*2)=1/3 or A

Where does this formula come from? The angle between two curves
from the tangent subtraction formula.
As and , the result follows.
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fleet street

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Re: VCE Methods Question Thread!
« Reply #2219 on: July 12, 2013, 09:30:42 am »
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I think that angle between two curves isn't on the study design. From the Essentials textbook, "This topic is not listed in the study design, but can be included for the understanding of other topics that are included."But yeah, it's good to know anyway. Also, if your teacher does decide to put it on SACs, then I guess you'd have to know it.
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