VCE Methods Question Thread!

[IndefatigableLover]

Lel, specialist doesn't cover variation. In fact, I may be wrong, but pretty sure that was a further thing.

Whoops I should have probably said GMA rather than Specialist since I remember doing a questions similar in GMA this year. My bad

[achre]

Whoops I should have probably said GMA rather than Specialist since I remember doing a questions similar in GMA this year. My bad

I can remember (I did GMA in yr 11) Kermond saying that variation isn't covered in spesh 3/4, but it is expected knowledge.

[keltingmeith]

I can remember (I did GMA in yr 11) Kermond saying that variation isn't covered in spesh 3/4, but it is expected knowledge.

It might be, but it's not really that big a thing (at least, I don't remember it in specialist...). The only time I've seen variation since year 10 was in physics last semester.

[IndefatigableLover]

I can remember (I did GMA in yr 11) Kermond saying that variation isn't covered in spesh 3/4, but it is expected knowledge.

Yeah I would listen to the man himself LOL but I had a check up on the Study Design for Methods/Specialist (since they're in the same file) and on Page 50 it talks about a Sample Course which includes Variation as a topic (though the course is more aimed at people doing Methods 3&4 next year). Having said that (and as others have also stated), down below to Page 172-173 is where you'd be most tested on in Specialist (no evidence of Variation).

(If you guys haven't you guys should definitely read the Study Design for Methods!)

[jessss0407]

Hey guys!

I have a question:
If Var(x)=25, how do you find sd(2-X)?

Thanks!

[keltingmeith]

Hey guys!

I have a question:
If Var(x)=25, how do you find sd(2-X)?

Thanks!

Hopefully you can follow that, I did skip a couple of steps.

[Bluegirl]

Help is needed please

A relation has rule y= 4-x/x-1, x doesn't = 1

Express. 4-x/x-1 in the form a/(x-1) + b.


How would I be this? Thankyou!

[Zealous]

A relation has rule y= 4-x/x-1, x doesn't = 1

Express. 4-x/x-1 in the form a/(x-1) + b.

where a=3 and b=-1.

You can also do this with long division if you want!

[~V]

Find the derivative of hence find
Thanks.

[keltingmeith]

Find the derivative of hence find
Thanks.

[LiquidPaperz]

can someone help with question 10a and b, with full working out and explanations please!!

ive attached q9 since you need some info from that


Thanks

Answers
a) This driver is 12.5 minutes behind the other driver.
b) 135 km/h.

[JHardwickVCE]

can someone help with question 10a and b, with full working out and explanations please!!

ive attached q9 since you need some info from that


Thanks

Answers
a) This driver is 12.5 minutes behind the other driver.
b) 135 km/h.

a)
Speed of Driver B=  150/75=2km/min
⇒Time to reach B=375/2=187.5 mins=3hrs 7.5mins
⇒Driver B is 12.5mins behind Driver A

b)
To catch up to Driver A, Driver B must travel 225km in 100 minutes (take time and distance difference between Checkpoint A and B)
100mins=1.67hrs
⇒Speed=  225/1.67=135km/h

[jessss0407]

hey guys!

I need some help with a few questions

1. if , then what is the derivative

2. The time, in days, that the flowers stay fresh is determined by distinct probability
density functions, unique to the type of flower.
For roses, the time Rt , in days, is a random variable with the probability density
function

For lilies, the time Lt, in days, that they stay fresh is normally distributed with a mean
of 7.2 days and a standard deviation of 1 day. Find the value of k, where k < 8 , such that the probability of each flower type lasting longer than k days is the same, correct to 2 decimal places. State the
value of k, correct to 2 decimal places.

3. How do I overcome "resource exhaustion" on CAS?

sorry for all the questions and thanks


-- whenever I try to work this out on my CAS, it says 'resource exhaustion' so is there another method to solve this?

[keltingmeith]

I'll jump onto the first one - not sure about the last one, sorry, and don't have time for the second.

hey guys!

I need some help with a few questions

1. if , then what is the derivative

Looks scary - but it's a double chain rule. If you have , then let . Now, using this, we have and . Now, in your situation, we have


and clean up as necessary.

[Phy124]

I usually opt to simplify logs before differentiating because in some cases it can decrease the chance of error.