VCE Methods Question Thread!

[knightrider]

There are infinitely many functions that satisfy the given property.
One simple example is .

Thanks q.e.d

[knightrider]

for the composite function to be defined the range of g domain of f.


so does this mean that for  the composite function to be defined the range of fdomain of g?

[cosine]

for the composite function to be defined the range of g domain of f.


so does this mean that for  the composite function to be defined the range of fdomain of g?

That's correct, because say f(x)=x, then f(1) = 1. Now, the final expression is g(f(x)), so g(f(1)) is g(1), as we find out what f(1) is and substitute the answer into g(x).

I hope that makes sense

[knightrider]

That's correct, because say f(x)=x, then f(1) = 1. Now, the final expression is g(f(x)), so g(f(1)) is g(1), as we find out what f(1) is and substitute the answer into g(x).

I hope that makes sense

thanks cosine 

[Sidha]

Hey guys. I had a practice test for methods today. It didn't go as well as I wanted to. It was on functions and linear relationships. I did well in the majority of the test, but found myself to be too casual. I ran out of time and was forced to leave out an application question which I could solve. I would have only missed 3 marks instead of 8. So now, I'm motivated even more and I am eager to redeem myself. I want to score a 35 raw in methods this year. I have my first sac in about 5-6 weeks and I believe it will focus on functions and relations, linear, families of functions and polynomials. So is there any advice someone can give me, preferably  someone who has completed methods and can remember sitting this sac?  Was your sac paper long? Were you pushed for time? Were there many application questions? Thanks in advance.

[point]

Hey guys. I had a practice test for methods today. It didn't go as well as I wanted to. It was on functions and linear relationships. I did well in the majority of the test, but found myself to be too casual. I ran out of time and was forced to leave out an application question which I could solve. I would have only missed 3 marks instead of 8. So now, I'm motivated even more and I am eager to redeem myself. I want to score a 35 raw in methods this year. I have my first sac in about 5-6 weeks and I believe it will focus on functions and relations, linear, families of functions and polynomials. So is there any advice someone can give me, preferably  someone who has completed methods and can remember sitting this sac?  Was your sac paper long? Were you pushed for time? Were there many application questions? Thanks in advance.

SACs will vary from school to school, so I think it's best to try past sac's from your school. Might have to ask some of your teachers for these but they really are a great way to practice!

Good luck!

[knightrider]

How would you do this question?

[keltingmeith]

How would you do this question?

f(g(x)), so we want the numbers coming out of g to go into f.
Range of g: [0, infinity)
Domain of f: R\{-a}

As long as we pick a to be positive, then the domain of f will also have a [0, infinity) in it (notice in the domain of f, we take the negative part?). So, the answer is

[Eiffel]

question asks:
In each case below, state the sequence of transformations required to transform the graph of the first equation into the graph of the second equation:

for y = 1/x to y = 2/(x-1) +3

i mentioned a dilation of 2 from the x axis, however answer has it from y axis. Is this stemmed from

y = 1/x to y = 1 / (1/2(x-1)) +3

but i dont see why they would do this when they could mention the x one?

This is similar to the question : y = ^3√x  to  y = 2 − ^3√(x+1), where they mention a reflection in either axis, is it not the x axis only?

[psyxwar]

question asks:
In each case below, state the sequence of transformations required to transform the graph of the first equation into the graph of the second equation:

for y = 1/x to y = 2/(x-1) +3

i mentioned a dilation of 2 from the x axis, however answer has it from y axis. Is this stemmed from

y = 1/x to y = 1 / (1/2(x-1)) +3

but i dont see why they would do this when they could mention the x one?

This is similar to the question : y = ^3√x  to  y = 2 − ^3√(x+1), where they mention a reflection in either axis, is it not the x axis only?

Both dilation from the x-axis and a dilation from the y-axis would do the same thing.

[Eiffel]

Ahh i see.

What i meant was the question asked state the transformations to "y = 1/x to y = 2/(x-1) +3"

and what i said, is y = 2/(x-1) +3 the same as y = 1 / (1/2(x-1)) +3 ?

[psyxwar]

Ahh i see.

What i meant was the question asked state the transformations to "y = 1/x to y = 2/(x-1) +3"

and what i said, is y = 2/(x-1) +3 the same as y = 1 / (1/2(x-1)) +3 ?

Yeah it is! Ignore what I said before, I think I was fried - the two are equivalent.

[#J.Procrastinator]

Hi guys I know this question is very easy but I'm stuck on one step.

The question is: -3=(x-2)(x+3)-9

I am trying to find the values of x via null factor law, however I don't know what to do when the is an -3 before the equals sign.

Bring the -3 to the right side so it becomes 0=(x-2)(x+3)-6. Expand the brackets then simplify and solve.

x^2 + x -12=0
(x+4)(x-3)=0
x= -4, x=3

[RazzMeTazz]

For any other TI inspire calculator uses, what happens when you press 'Ctrl + var' button?

I was going through matrices in the Year.11 Essentials Textbook (just as revision) and in the examples they have entered matrices and then pressed 'Ctrl+var' to store the matrix?

However, when I press 'ctrl+var' nothing seems to happen on my screen. It is as if I had not pressed anything at all

[Eiffel]

for the anti derivative of 1/ax+b why must there be an absolute value sign e.g. 1/a loge|...| ?

i know it needs to be greater then 0 but is there a reason? indefinite?