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November 06, 2025, 08:58:40 am

Author Topic: My Exam 1 answers  (Read 14163 times)  Share 

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hyperblade01

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Re: My Exam 1 answers
« Reply #15 on: October 30, 2009, 05:36:54 pm »
Also for Q 3 I just left it as perpendicular component = blah blah and parallel component = blah blah. Do you guys think that's fine?


If it makes you feel better, I also did that :P
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TonyHem

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Re: My Exam 1 answers
« Reply #16 on: October 30, 2009, 05:37:30 pm »
I think it's just me but I can't read latex? it's coming up in code form

bloodboy

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Re: My Exam 1 answers
« Reply #17 on: October 30, 2009, 05:37:36 pm »
my bad didnt see the small -

TrueTears

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Re: My Exam 1 answers
« Reply #18 on: October 30, 2009, 05:37:42 pm »
Awesome! Looks like everything else is fine to me.
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philza

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Re: My Exam 1 answers
« Reply #19 on: October 30, 2009, 05:44:02 pm »
Jimmy you got your end tags the wrong way around should be [/tex] not [\tex]
how could you solve k, there wasnt any boundary conditions

Um can someone explain this to me? I also don't see how you can solve for k ... :/   
That intergral to solve v in terms of x is very depressing -.-"

TrueTears

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Re: My Exam 1 answers
« Reply #20 on: October 30, 2009, 05:44:34 pm »
Jimmy you got your end tags the wrong way around should be [/tex] not [\tex]
how could you solve k, there wasnt any boundary conditions

Um can someone explain this to me? I also don't see how you can solve for k ... :/   
That intergral to solve v in terms of x is very depressing -.-"
sub (1,1) into the original equation.
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

dav132

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Re: My Exam 1 answers
« Reply #21 on: October 30, 2009, 05:44:59 pm »
what!?
i don't get how we were meant to find k??
it didn't not say to write the gradient in terms of k.
I just left it as -7-k,
do u guys reckon i'll lose marks for that?? :S
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tomygun_123

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Re: My Exam 1 answers
« Reply #22 on: October 30, 2009, 05:45:07 pm »
i dont think you could solve for K, in the previous question it asked to solve in terms of k, x and y so you could just leave dy/dx in terms of k... just a thought.
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TonyHem

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Re: My Exam 1 answers
« Reply #23 on: October 30, 2009, 05:46:01 pm »
You can solve for K
and yeah you will lose a mark
(JOIN ME: HAHAH I didn't solve for K either  :-X)

dav132

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Re: My Exam 1 answers
« Reply #24 on: October 30, 2009, 05:46:10 pm »
ah yeh, that makes sense.
but still, it didn't say find k!! :'(
2008: Maths Methods CAS [43] Physics [34]
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d0minicz

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Re: My Exam 1 answers
« Reply #25 on: October 30, 2009, 05:46:43 pm »
what!?
i don't get how we were meant to find k??
it didn't not say to write the gradient in terms of k.
I just left it as -7-k,
do u guys reckon i'll lose marks for that?? :S
maybe because the question didnt say gradient in terms of k
i did the same as u
what was that out of ? that part
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hyperblade01

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Re: My Exam 1 answers
« Reply #26 on: October 30, 2009, 05:48:28 pm »
I reckon 2 marks

EDIT: Yea i think it was as the page was 2, 2, 2
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gilla

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Re: My Exam 1 answers
« Reply #27 on: October 30, 2009, 05:48:36 pm »
my Question 9
a) y = -2 +2tan{(2x + \frac{\pi}{4})}

my tan wasnt simplified, do you think they'd take marks off?

TonyHem

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Re: My Exam 1 answers
« Reply #28 on: October 30, 2009, 05:48:54 pm »
what!?
i don't get how we were meant to find k??
it didn't not say to write the gradient in terms of k.
I just left it as -7-k,
do u guys reckon i'll lose marks for that?? :S
maybe because the question didnt say gradient in terms of k
i did the same as u
what was that out of ? that part
2 mark question I think

TrueTears

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Re: My Exam 1 answers
« Reply #29 on: October 30, 2009, 05:49:31 pm »
2 mark question.

I *think* it's 1 mark 1 subbing in the right value of k.

Another mark for the right answer.
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.