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July 22, 2025, 09:11:04 pm

Author Topic: Maths Methods 3/4 Help Thread 2011  (Read 126618 times)  Share 

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Tobias Funke

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Re: Maths Methods 3/4 Help Thread
« Reply #195 on: June 07, 2011, 09:19:34 pm »
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For composite functions, what defines the domain and range?
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brightsky

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Re: Maths Methods 3/4 Help Thread
« Reply #196 on: June 07, 2011, 09:35:15 pm »
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i think you need to work with it case by case. i don't think there is an explicit 'formula' that defines the dom and ran for composite functions.
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Re: Maths Methods 3/4 Help Thread
« Reply #197 on: June 09, 2011, 04:20:54 pm »
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For composite functions, what defines the domain and range?

Well, for fog (or f(g(x)) ) to exist, Ran g must be a subset (or equal to) Dom f. That's pretty much the only 'defining' part of it, as brightsky posted, its fairly case-by-case.

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Re: Maths Methods 3/4 Help Thread
« Reply #198 on: June 17, 2011, 06:37:50 pm »
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Heyy! Im stuck on this one question whilst doing differentiation, i really need help

i have to derive----> (x^2+1)(2x-4)^1/2

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Re: Maths Methods 3/4 Help Thread
« Reply #199 on: June 17, 2011, 06:46:36 pm »
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let u = x^2+1, u'=2x, v=(2x-4)^1/2, v'=1/2*(2x-4)^-1/2*2
derivative = u'v+v'u, =(x^2+1)*(2x-4)^-1/2 + 2x*(2x-4)^1/2. you can leave it as this or make it a whole fraction, doesnt really matter.
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Re: Maths Methods 3/4 Help Thread
« Reply #200 on: June 18, 2011, 08:45:45 pm »
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Hey,
I'm having trouble differentiating the following with respect to x:

any help would be great :)
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Re: Maths Methods 3/4 Help Thread
« Reply #201 on: June 18, 2011, 08:50:59 pm »
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So we have simplified
so
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ech_93

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Re: Maths Methods 3/4 Help Thread
« Reply #202 on: June 19, 2011, 12:25:11 pm »
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I need to find x when

All the x's get me confused, and its a non-calculator question...
???
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Re: Maths Methods 3/4 Help Thread
« Reply #203 on: June 19, 2011, 12:26:58 pm »
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x=-1? move the square root to the left hand side
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ech_93

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Re: Maths Methods 3/4 Help Thread
« Reply #204 on: June 19, 2011, 12:28:38 pm »
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x=-1? move the square root to the left hand side

Oh, wow. That was so obvious, how didn't I realise that -__-

Thanks! :)
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Re: Maths Methods 3/4 Help Thread
« Reply #205 on: June 19, 2011, 03:12:12 pm »
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Another question... I need to differentiate as part of a question. I'm getting by hand, but CAS is telling me
what am i doing wrong :(
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Re: Maths Methods 3/4 Help Thread
« Reply #206 on: June 19, 2011, 03:15:03 pm »
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you forgot the chain rule. multiply the (6x)' = 6 and you've got the answer (expressed in different form).
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Re: Maths Methods 3/4 Help Thread
« Reply #207 on: June 19, 2011, 03:17:54 pm »
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Hint: chain rule then rationalise it.
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Re: Maths Methods 3/4 Help Thread
« Reply #208 on: June 19, 2011, 10:03:42 pm »
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Infact you don't even need to use the chain rule just break sqrt(6x) into sqrt(6) x sqrt(x) then the sqrt(6)
is just a constant and all you have to do is just derive the sqrt(x) and you'll get the same answer  :)

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Re: Maths Methods 3/4 Help Thread
« Reply #209 on: June 21, 2011, 05:18:04 pm »
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I came across a question; " explain how you can find the derivatives of sin(x), cos(x) and tan(x)?"
How would you go about answering this question? Would you explain how to find it through actually looking at the graph (by this i mean, how you can look at the turning points and they tell you where your x-intercepts are, etc) or a different way?

Please help, thankyou :)
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